Answer:Velocity = 6.325m/s
Directional angle= 18.43°
Explanation:
Using Right angle triangle
Let Velocity of ballon&hawk be VHB represent the height of the triangle.
Let Velocity of balloon angle ground be VBG represent adjacent of the triangle.
Let Velocity of hawk and ground BE VHG represent the hypothesis.
Theta = opp/Adj= VHB/VBG
using pythagorean
VHG= SQRT(VHB^2+VBG^2)
VHG= sqrt(2^2+6^2)
VHG= sqrt(4+36)
VHG= 6.325m/s
Tan theta= 2/6
Tan theta =0.3333
Tan^-1 0.3333=18.43°
Answer:
The 
electrons are moving through the superconductor per second.
Explanation:
Given :
Current 
A
Charge of electron 
C
Time 
sec
From the formula of current,
Current is the number of charges flowing per unit time.
Where 
number of charges means in our case number of electrons
Therefore, electrons are moving through the superconductor per second.
The change in momentum of an object equals the impulse applied to it
Answer:
Object 2, which has a density of 1.9 g/cm3, since it has more density than freshwater.
