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klemol [59]
3 years ago
11

Hii! help asap. i’ll give brainliest thanks!

Physics
1 answer:
telo118 [61]3 years ago
7 0
Its acceleration will change
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A 6.00 g lead bullet traveling at420 m/s is stopped by a large
Westkost [7]

Answer:

The increase in temperature of the bullet is 351.1 kelvin

Explanation:

First, we should find the kinetic energy of the bullet is:

K=\frac{mv^{2}}{2}=\frac{(6\times10^{-3}\,kg)(420\,\frac{m}{s})^{2}}{2}

with m the mass and v the velocity.

K=529.2 J

Now we know that half of the kinetic energy of the bullet is transformed into internal energy, by second's law of thermodynamics that means heat (Q) to raise bullet temperature (T), so:

Q=\frac{K}{2}= 264.6\,J

To know what the increase in temperature is, we should use specific heat of lead:

c=125.604 \frac{J}{kg\.K}

The equation that relates specific heat, change in temperature and mass is:

Q=cm\varDelta T

solving for \varDelta T:

\varDelta T=\frac{Q}{cm}=\frac{264.6}{(125.604)(6\times10^{-3})}

\varDelta T= 351.10\, K

4 0
3 years ago
2. What is the kinetic energy of an 80 kg football player running at 8m/s? *
alexdok [17]

Answer:

the answer is A!! 2560 J

5 0
3 years ago
Read 2 more answers
An industrial overhead door has a chain and sprocket system designed to reduce the force needed by an operator to open and close
mylen [45]
GR/1=nout/nin = 48/22=2.18/1
4 0
3 years ago
A 1.00 x 104 W electric motor is used to lift a
Alexus [3.1K]

Answer: 52%

Explanation:

1W = 1 J/s

motor input is 10000 J/s

Potential energy change

PE = 955(9.81)(25.0) = 234,213.75

power needed to change the PE in that time

P = 234,213.75/ 45 = 5,204.75 Watts

motor is 5204.75 / 10000 = 0.520475 or 52% efficient

4 0
3 years ago
"Suppose you tie a rock to the end of a 0.96 m long string and spin it in a horizontal circle with a constant angular velocity o
Ber [7]

Answer:

The mass of the rock is  m = 2.46406 \ kg

Explanation:

From the question we are told that

   The length of the string is  l  = 0.96 \ m

    The angular velocity is  w =  20.25 \ rad/s

     The tension on the string is T  = 970 \ N

Generally the centripetal force acting on the rock is mathematically evaluated as

       T = mlw^2

making m the subject of the formula

      m = \frac{T}{w^2 * l}

substituting values

     m = \frac{970}{(20.25^2) * (0.96)}

     m = 2.46406 \ kg

       

8 0
3 years ago
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