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klemol [59]
3 years ago
11

Hii! help asap. i’ll give brainliest thanks!

Physics
1 answer:
telo118 [61]3 years ago
7 0
Its acceleration will change
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What is part of a line has one endpoint and continues in one direction?
noname [10]

Answer:

A Ray I believe since it sounds like it.

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3 years ago
You're staring at a traditional clock for 1 hour. after 1 hour, what is the angular displacement of the second hand? the minute
Anvisha [2.4K]
<span>During the hour, the second hand will have traveled a full 360 degrees times 60 for a total displacement of 21600 degrees or 21600*pi/180 = 120 pi radians, or approximately 376.99 radians. Also during that hour, the minute hand will have gone around a full 360 degrees, or 360*pi/180 = 2 pi radians, or approximately 6.28 radians. And finally, the hour hand will have gone 360/12 = 30 degrees or 30*pi/180 = pi/6 radians, or approximately 0.52 radians.</span>
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3 years ago
A body of mass 1kg has a 25kgsmsqure moment of inertia about its center of mass. if it rotated about an axis which has a displac
ASHA 777 [7]

Answer:

194 kg m²

Explanation:

Use parallel axis theorem:

I = I₀ + mr²

I = 25 kg m² + (1 kg) ((5 m)² + (12 m)²)

I = 25 kg m² + 169 kg m²

I = 194 kg m²

6 0
3 years ago
The rectangular boat shown below has base dimensions 10.0 cm × 8.0 cm. Each cube has a mass of 40 g, and the liquid in the tank
Paladinen [302]

When boat is sunk into the liquid the net buoyancy on the boat is counterbalanced by weight of the boat

So here weight of the boat = Buoyancy force

let say boat is sunk by distance "h"

now we can say

F_b = \rho * V * g

F_b = 1000*0.10 * 0.08 * h * 9.8

now by above force balance equation we can write

m*g = F_b

0.040 * 9.8 = 1000 * 0.10 * 0.08 * h * 9.8

0.040 = 8h

h = 5 * 10^{-3} m

so boat will sunk by total 5 mm distance

8 0
3 years ago
An electron accelerated from rest through a voltage of 780 v enters a region of constant magnetic field. part a part complete if
maxonik [38]
The electron is accelerated through a potential difference of \Delta V=780 V, so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:
\frac{1}{2}mv^2 =  e \Delta V
where
m is the electron mass
v is the final speed of the electron
e is the electron charge
\Delta V is the potential difference

Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:
v= \sqrt{ \frac{2 e \Delta V}{m} } = \sqrt{ \frac{2(1.6 \cdot 10^{-19}C)(780 V)}{9.1 \cdot 10^{-31} kg} }=1.66 \cdot 10^7 m/s


Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:
evB=m \frac{v^2}{r}
where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:
B= \frac{mv}{er}= \frac{(9.1 \cdot 10^{-31}kg)(1.66 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19}C)(0.25 m)} =3.8 \cdot 10^{-4} T
3 0
4 years ago
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