Hii! help asap. i’ll give brainliest thanks!

A seagull flies at a velocity of 9.00 m/s straight into the wind.

RideAnS [48]

a)If it takes the bird 18.0 minutes to fly 6 km away from the earth, the wind's speed will be 4 m/s.

b) The bird would need 7 minutes and 42 seconds to fly back 6 kilometers if he turned around and flew with the wind.

c)Compared to the 133.33 seconds it would take without the wind, the overall round-trip time is affected by the wind.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

A seagull flies at a velocity, $\rm v_{SA} = 9 \ m/sec$

The time the bird takes,t=18.0 min

The distance traveled relative to the earth = 6.00 km

a)

The seagull's relative velocity with reference to the ground as;

$\rm v_{sg} = \frac{6.00 \times 10^3 \ m }{(20 min) \times \frac{60 s }{1 \ min}} \\\\ v_{sg}= 5.00 \ m/sec$

Air velocity with reference to the ground is;

$\rm v_{AG}= v_{SG}-v_{SA} \\\\ v_{AG} = 5.00 \ m/sec - 9.00 \ m/sec \\\\ v_{AG} = -4.00 \ m/sec$

b)

If the bird turns around and flies with the wind, The time will he take to return 6.00 km is;

$\rm v_{SG}=v_{SA}+v_{AG} \\\\ v_{SG}=-900 \ m/sec +(-4.00 \ m/sec) \\\\ v_{SG}= -13.00 \ m/sec$

The time the bird takes;

$\rm t = \frac{x_{SG}}{v_{SG}} \\\\ t = \frac{6.00 \times 10^3 \ m }{13.00 \ m/sec } \\\\ t = 462 m/sec \\\\ t = 7 \ min \ and \ 42 \ sec$

c)\

The total round-trip time compared to what it would be with no wind. is;

$\rm t = 20 \ min( \frac{60 \ sec }{1 \ min} )+ 462 \ sec \\\\ t = 1200 \ sec +6 462 \ ec \\\\ t= 1662 \ sec$

The time for the round trip is;

$\rm t = \frac{12 \times 10^ 3 }{ 9 \ m/sec } \\\\ t = 1333.33 \ sec$

Hence the wind's speed, the time bird would need to fly back the total round-trip time will be 4 m/s, 7 minutes and 42 seconds and 1333.33 sec.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

4 0

2 years ago

If the forces acting on a soccer ball are balanced , what should happen to the motion of the ball? A The ball will fall to the g

lukranit [14]

That’s what she said

5 0

3 years ago

Read 2 more answers

The following charges are located inside a submarine: 2.75 μC, −9.00 μC, 27.0 μC, and −43.5 μC.(a) Calculate the net electric fl

Kaylis [27]

Answer with Explanation:

We know that by Gauss's Law

$E\cdot Flux=\frac{q_{inside}}{\epsilon _o}$

Where

$\epsilon _o$ is permitivity of free space

$q_{inside}$ is the net charge in the hull

Part a)

Applying the given values we get

$E\cdot Flux=\frac{(2.75+27-9-43.5)\times 10^{-6}C}{8.85\times 10^{-12}}\\\\\therefore E\cdot flux=-2.5\times 10^{6}$

Part b)

Since the sign of the electric flux is negative we conclude that the electric field lines entering the submarine are more than the electric field lines leaving the submarine. Since negative sign implies that flux by negative charges is dominant.

7 0

3 years ago

Explain in detail , four physical properties of metals

astraxan [27]

Answer:

Explanation:

Physical properties are usually those that can be observed using our senses such as color, luster, freezing point, boiling point, melting point, density, hardness and odor. Metalloids have mixed properties which are difficult to characterize. Conductivity: Semi-conductive.

3 0

3 years ago

A ray of light traveling in water (n = 1.33) is incident at the flat surface of a block of glass (n = 1.60). If the incident ray

Rudik [331]

Answer:

θ₂ ≈ 29.7°

Explanation:

Given:

n₁ = 1.33, n₂= 1.60, θ₁ = 36.6°, θ₂ = ?

Solution:

According to snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1.33 × sin (36.6°) = 1.60 × sin θ₂

⇒ Sin θ₂ = 0.496

θ₂ ≈ 29.7°

5 0

3 years ago