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klemol [59]
2 years ago
11

Hii! help asap. i’ll give brainliest thanks!

Physics
1 answer:
telo118 [61]2 years ago
7 0
Its acceleration will change
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What is the difference between fertilization and pollination
lana [24]
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3 years ago
If you will be rinsing your regulator after removing it from the cylinder, you must make sure that the ______ ______ is firmly i
Rudik [331]

If you will be rinsing your regulator after removing it from the cylinder, you must make sure that the dust cap is firmly in place.

<h3>What is Dust cap?</h3>

A dust cap is a gently curved dome mounted either in concave or convex orientation over the central hole of most loudspeaker diaphragms.

Thus, if you will be rinsing your regulator after removing it from the cylinder, you must make sure that the dust cap is firmly in place.

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5 0
2 years ago
Calculate the density of water in kg/m3. Express your answer in kilograms per cubic meter using three significant figures.
Svet_ta [14]

Answer:

This question appear incomplete

Explanation:

This question appear incomplete. However, the density of water is generally known to be 997 kg/m³. The formula used to determine density is mass ÷ volume. In the case of the density of water, the mass is measured in kilograms (kg) while the volume is measured in cubic meter (m³).

8 0
3 years ago
A model rocket is fired vertically upward from rest. Its acceleration for the first three seconds is a(t) = 66 t, at which time
musickatia [10]

(x=yt-2)^2(56-tea)^2x10r

5 0
3 years ago
The coordinates of a particle in the metric​ xy-plane are differentiable functions of time t with StartFraction dx Over dt EndFr
Brut [27]

Answer:

\dfrac{dD}{dt}=-7.076\ m/s

Explanation:

It is given that,

The coordinates of a particle in the metric​ xy-plane are differentiable functions of time t are given by :

\dfrac{dx}{dt}=-6\ m/s

\dfrac{dy}{dt}=-4\ m/s

Let D is the distance from the origin. It is given by :

D^2=x^2+y^2

Differentiate above equation wrt t as:

2D\dfrac{dD}{dt}=2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}

D\dfrac{dD}{dt}=x\dfrac{dx}{dt}+y\dfrac{dy}{dt}.............(1)

The points are given as, (12,5). Calculating D from these points as :

D=\sqrt{12^2+5^2} =13\ m

Put all values in equation (1) as :

13\times \dfrac{dD}{dt}=12\times (-6)+5\times (-4)

\dfrac{dD}{dt}=-7.076\ m/s

So, the particle is moving away from the origin at the rate of 7.076 m/s. Hence, this is the required solution.

4 0
3 years ago
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