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mezya [45]
3 years ago
9

Which organ in frog function similar to the function of lungs in a bird ?​

Chemistry
1 answer:
34kurt3 years ago
3 0

Answer:

Explanation:

FROGS BREATHE THROUGH SKIN IN WATER AND THROUGH LUNGS ON LAND.

I HOPE IT WILL HELP YOU.

Hope this will help you and please mark as brainlist answer

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Consider the balanced equation below. 4nh3 3o2 right arrow. 2n2 6h2o what is the mole ratio of nh3 to n2? 2:4 4:2 4:4 7:2
KIM [24]

The required mole ratio of  NH₃ to N₂ in the given chemical reaction is 2:4.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.

Given chemical reaction is:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

From the stoichiometry of the reaction it is clear that:

4 moles of NH₃ = produces 2 moles of N₂

Mole ratio NH₃ to N₂ is 2:4.

Hence required mole ratio is 2:4.

To know more about mole ratio, visit the below link:
brainly.com/question/504601

3 0
2 years ago
Traveling at the speed of light - how long would it take, in years, to reach the top of the pile of balls? Show all calculations
marusya05 [52]

The time taken for the object to reach to top of pile is 0.012 year.

<h3>Time of motion </h3>

The time taken for the object to reach to top of pile is calculated as follows;

time of motion = distance traveled/speed

time of motion = (1.1 x 10¹⁴ x 10³ m)/(3 x 10⁸ m/s)

where;

  • speed of light = 3 x 10⁸ m/s

time of motion = 3.67 x 10⁵ sec = 0.012 year

Thus, the time taken for the object to reach to top of pile is 0.012 year.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

7 0
2 years ago
What is the equilibrium equation for the dissociation of formic acid in water? hcooh (aq) + h2o (l) ⇌ h3o+ (aq) + hcoo- (aq)?
Pani-rosa [81]
Formic acid when in water would dissociate into ions just like any acids. It would dissociate into the hydrogen ion and the formate ion. The equilibrium dissociation equation would be written as:

<span>HCOOH (aq) + H2O (l) ⇌ H+ (aq) + HCOO- (aq)

Formic acid is a weak acid which means that when in aqueous solution it does not completely dissociate into its corresponding ions. Only a certain amount that would be dissociated so in the solution there will be HCOOH, HCOO- and H+ molecules. It is also known as Methanoic acid and an important substance for the synthesis of a number of substances. It is naturally occurring in ants.</span>
7 0
3 years ago
How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous sol
mojhsa [17]

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

2Al + 3Cu{(NO_3)}_2  \rightarrow 2Al{(NO_3)}_3 +3 Cu

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

Al \rightarrow Al^{3+} + 3e^-

And copper goes from +2 to 0

Cu^{2+} + 2e^-\rightarrow Cu

On balancing the number of electrons we get:

For 1 mole of Al 6e^- is required.

Therefore for 2 moles of Al,

Total (2\times6)F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

brainly.com/question/27985929

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4 0
1 year ago
In a 1.0× 10–6 M solution of Ba(OH)2(aq) at 25 °C, identify the relative molar amounts of these species.
Marysya12 [62]
Thank you for posting your question here. Below is the solution:

HNO3 --> H+ + NO3- 
<span>HNO3 = strong acid so 100% dissociation </span>
<span>** one doesn't need to find the molarity of water since it is the solvent </span>

<span>0M HNO3 </span>
<span>1x10^-6M H3O+ </span>
<span>1x10^-6M NO3- </span>
<span>1x10^-8M OH-.....the Kw = 1x10^-14 = [H+][OH-] </span>
<span>you have 1x10^-6M H+ so, 1x10^-14 / 1x10^-6 = 1x10^-8M OH- </span>


<span>1x10^-6 Ba(OH)2 = strong base, 100% dissociation </span>
<span>1x10^-6M Ba2+ </span>
<span>2x10^-6M OH- since there are 2 OH- / 1 Ba2+ </span>
<span>0M Ba(OH)2 </span>
<span>5x10^-9M H3O+</span>
4 0
3 years ago
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