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2 years ago

How does an increase in greenhouse gases in the atmosphere cause an increase in global temperature?

Physics

1 answer:

daser333 [38]2 years ago

8 0

Answer:

<h2>Greenhouse gases absorb and emit radiation and less heat dissipates to space</h2>

Explanation:

when heat is trapped it is conducted to the trapped area and gradually heats up its surrounding

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1 year ago

A 500 G ball and a 200 g or dropped from a tower. Those balls are the same size and there is no air resistance. Which one hits t

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They both hit at the same time

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3 years ago

Read 2 more answers

Consider the following setup with three identical springs, a ruler for length measurements and three known masses and three unkn

svetlana [45]

Answer:

To find the value of the unknown weight, we previously placed the 3 known weights and made a graph of the force against displacement

When hanging the weight is known, we measure the displacement and from the graph we can find the value of the hanging masses

We can also use the equation and multiply the constant K by the displacement and this is the applied weight.

Explanation:

For this problem we will use the translational equilibrium relation

F –W = 0

F = W

W = mg

The spring elastic force is

F = - k x

We substitute

k x = m g

Where we see that the force of the spring is equal to the weight of the body.

To find the value of the unknown weight, we previously placed the 3 known weights and made a graph of the force against displacement

When hanging the weight is known, we measure the displacement and from the graph we can find the value of the hanging masses

We can also use the equation and multiply the constant K by the displacement and this is the applied weight.

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3 years ago

Which of the following statements is true?

vampirchik [111]

Option. c freezing and melting temperature of wster is=0 degree celcius roght? but boiling temperature is=100degree celcius

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3 years ago

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A point charge of 3 µC is located at x = -3.0 cm, and a second point charge of -10 µC is located at x = +4.0 cm. Where should a

Nataly [62]

Answer:

The charge q₃ must be placed at X = +2.5 cm

Explanation:

Conceptual analysis

The electric field at a point P due to a point charge is calculated as follows:

E = k*q/d²

E: Electric field in N/C

q: charge in Newtons (N)

k: electric constant in N*m²/C²

d: distance from charge q to point P in meters (m)

The electric field at a point P due to several point charges is the vector sum of the electric field due to individual charges.

Equivalences

1µC= 10⁻6 C

1cm= 10⁻² m

Data

k = 8.99*10⁹ N×m²/C²

q₁ =+3 µC =3*10⁻⁶ C

q₂ = -10 µC =-10*10⁻⁶ C

q₃= +6µC =+6*10⁻⁶ C

d₁ = 3cm =3×10⁻² m

d₂ = 4cm = 4×10⁻² m

Graphic attached

The attached graph shows the field due to the charges:

E₁:Field at point P due to charge q₁. As the charge is positive ,the field leaves the charge. The direction of E1 is (+ x).

E₂: Field at point P due to charge q₂. As the charge is positive ,the field leaves the charge. The direction of E1 is (+ x).

Problem development

E₃: Field at point P due to charge q₃. As the charge q₃ is positive, the field leaves the charge.

The direction of E₃ must be (- x) so that the electric field can be equal to zero at point P since E₁ and E₂ are positive, then, q₃must be located to the right of point P.

We make the algebraic sum of fields at point P due to the charges q1, q2, and q3:

E₁+E₂-E₃=0

$\frac{k*q_{1} }{d_{1}^{2} } +\frac{k*q_{2} }{d_{2}^{2} } -\frac{k*q_{3} }{d_{3}^{2} } =0$

We eliminate k

$\frac{q_{1} }{d_{1} ^{2} } +\frac{q_{2} }{d_{2} ^{2} }+\frac{q_{3} }{d_{3} ^{2} }=0$

We replace data

$\frac{3*10^{-6} }{(3*10^{-2})^{2} } +\frac{10*10^{-6} }{(4*10^{-2})^{2} } +\frac{6*10^{-6} }{d_{3} ^{2} } =0$

we eliminate 10⁻⁶

$\frac{3}{9*10^{-4} } +\frac{10}{16*10^{-4} } =\frac{6}{d_{3}^{2} }$

$(\frac{1}{10^{-4} }) *(\frac{1}{3} +\frac{5}{8}) =\frac{6}{d_{3}^{2} }$

$\frac{23*10^{4} }{24} =\frac{6}{d_{3} ^{2} }$

$d_{3} =\sqrt{\frac{6*24}{23*10^{4} } }$

$d_{3} =2.5*10^{-2} m\\d_{3} =2.5 cm$

The charge q₃ must be placed at X = +2.5 cm

6 0

2 years ago