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Darina [25.2K]
3 years ago
9

What is the normal force when a 40 kg person jumps and is accelerating at 3 m/s2 upward while in contact with the ground?

Physics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

N=mg

g=10-3=7

n=40×7

n=280

Explanation:

please make me brainiest if it helps you

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3 years ago
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Nataly [62]

Answer:

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Explanation:

From the question we are told that  

       The  initial speed is  u  =  28 \  m/s at a distance of  s_1  =  0 \ m

        The  final speed is  v  =  0 \  m/s    at a distance of  s_2 =  88 \  m

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