Question

A gas tank is known to have a thickness of 0.5 inches and an internal pressure of 2.2 ksi. Assuming that the maximum allowable shear stress in the tank wall is 12 ksi, determine the necessary outer diameter for the tank. Assume that the tank is made of a cold drawn steel whose elastic modulus is 35000 ksi and whose Poisson ratio is 0.292. If y

Answer 1

Answer:

$D_o=11.9inch$

Explanation:

From the question we are told that:

Thickness $T=0.5$

Internal Pressure$P=2.2Ksi$

Shear stress $\sigma=12ksi$

Elastic modulus $\gamma= 35000$

Generally the equation for shear stress is mathematically given by

 $\sigma=\frac{P*r_1}{2*t}$

Where

r_i=internal Radius

Therefore

 $12=\frac{2.2*r_1}{2*0.5}$

 $r_i=5.45$

Generally

 $r_o=r_1+t$

 $r_o=5.45+0.5$

 $r_o=5.95$

Generally the equation for outer diameter is mathematically given by

 $D_o=2r_o$

 $D_o=11.9inch$

Therefore

Assuming that the thin cylinder is subjected to integral Pressure

Outer Diameter is

 $D_o=11.9inch$