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2 years ago

Explain race condition..don't spam..

Engineering

2 answers:

rodikova [14]2 years ago

7 0

Answer:

A race condition or race hazard is the condition of an electronics, software, or other system where the system's substantive behavior is dependent on the sequence or timing of other uncontrollable events.

Explanation:

hope this helps you!!

nalin [4]2 years ago

6 0

There are lot of factors that influences race. The explanation of the term is given below.

<h3>What is the race condition?</h3>

A race condition is known to be a type of situation that one finds to be unattractive or undesirable.

This type of condition often takes when a tool, device or system tries every possible way to carry out two or more work at the same time, but due to the the nature of the tool, device or system, the work have to be done in a sequential manner or the right steps so that there will be no error.

A common and well known example of a race condition is the light switch.

Learn more about race condition from

brainly.com/question/13445523

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Some Tiny College staff employees i s are information technology (IT) personnel. Some IT personnel provide technology support fo

Westkost [7]

Answer:

solution in the picture attached

Explanation:

3 0

3 years ago

Using the degree day method calculate the annual kwh use in springfiled il with a heat loss of 12kwh an inddor twmperature of 7

vladimir2022 [97]

Answer:

The correct solution is "21024 KWh/degree day".

Explanation:

The given query is incomplete. Below is the attachment of complete query is provided.

The given values are:

Indoor design temperature:

= 70°F

Now,

According to the question,

The heat loss annually will be:

= $12\times 24\times 365$

= $105120 \ KW$

Degree days will be:

= $75-65$

= $5$

Hence,

Annual KWh use will be:

= $\frac{Heat \ loss \ annually}{degree \ days}$

On substituting the values, we get

= $\frac{105120}{5}$

= $21024 \ KWh/degree \ day$

8 0

3 years ago

(1) Prompt the user for the number of cups of lemon juice, water, and agave nectar needed to make lemonade. Prompt the user to s

Lady bird [3.3K]

Answer:

The program to this question as follows:

Program:

Lemon= float(input('Enter lemon juice value in cups: ')) #defining float variable and input value by user

Water= float(input('Enter water value in cups: ')) #defining float variable and input value by user

Agave= float(input('Enter agave nectar value in cups: ')) #defining float variable and input value by user

Serve= float(input('enter serving value: ')) #defining float variable and input value by user

print ('Lemonade ingredients - yields',Serve,'servings',) #print value

print (Lemon,'cups in lemon juice',) #print value

print (Water,'cups in water',) #print value

print (Agave,'cups in agave nectar',) #print value

Output:

Enter lemon juice value in cups: 2

Enter water value in cups: 3

Enter agave nectar value in cups: 2

enter serving value: 2

Lemonade ingredients - yields 2.0 servings

2.0 cups in lemon juice

3.0 cups in water

2.0 cups in agave nectar

Explanation:

In the above python code, four float variable "Lemon, Water, Agave, and Serve" is defined, which is the input function is used.

The input function message is written that passes in function parameter, that accepts value in the above variables.
In the next step, the print function is used, which prints the above user input values.

6 0

4 years ago

A square aluminum plate 5 mm thick and 150 mm on a side is heated while vertically suspended in quiescent air at 75°c. determine

Doss [256]

By using the boundary layer equation, the average heat transfer coefficient for the plate is equal to 4.87 W/m²k.

<u>Given the following data:</u>

Surface temperature = 15°C

Bulk temperature = 75°C

Side length of plate = 150 mm to m = 0.15 meter.

<h3>How to calculate the average heat transfer coefficient.</h3>

Since we have a quiescent room air and a uniform pole surface temperature, the film temperature is given by:

$T_f=\frac{T_{s} + T_{\infty} }{2} \\\\T_f=\frac{15 + 75 }{2} \\\\T_f = 45$

Film temperature = 45°C to K = 273 + 45 = 318 K.

For the coefficient of thermal expansion, we have:

$\beta =\frac{1}{T_f} \\\\\beta =\frac{1}{318}$

From table A-9, the properties of air at a pressure of 1 atm and temperature of 45°C are:

Kinematic viscosity, v = $1.750 \times 10^{-5}$ m²/s.

Thermal conductivity, k = 0.02699 W/mk.

Thermal diffusivity, α = $2.416 \times 10^{-5}$ m²/s.

Prandtl number, Pr = 0.7241.

Next, we would solve for the Rayleigh number to enable us determine the heat transfer coefficient by using the boundary layer equations:

$R_{aL}=\frac{g\beta \Delta T l^3}{v\alpha } \\\\R_{aL}=\frac{9.8 \;\times \;\frac{1}{318} \;\times \;(75-15) \;\times \;0.15^3 }{1.750 \times 10^{-5}\; \times \;2.416 \times 10^{-5} } \\\\R_{aL}=\frac{9.8\; \times 0.00315 \;\times \;60\; \times\; 0.003375 }{4.228 \times 10^{-10} }\\\\R_{aL}=1.48 \times 10^{7}$

Also take note, g(Pr) is given by this equation:

$g(P_r)=\frac{0.75P_r}{[0.609 \;+\;1.221\sqrt{P_r}\; +\;1.238P_r]^\frac{1}{4} } \\\\g(P_r)=\frac{0.75(0.7241)}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[2.5444]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{1.2630 }$

g(Pr) = 0.430

For GrL, we have:

$G_{rL}=\frac{R_{aL}}{P_r} \\\\G_{rL}=\frac{1.48 \times 10^7}{0.7241} \\\\G_{rL}=1.99 \times 10^7$

Since the Rayleigh number is less than 10⁹, the flow is laminar and the condition is given by:

$N_{uL}=\frac{h_{L}L}{k} = \frac{4}{3} (\frac{G_{rL}}{4} )^\frac{1}{4} g(P_r)\\\\h_{L}=\frac{0.02699}{0.15} \times [\frac{4}{3} \times (\frac{1.99 \times 10^7}{4} )^\frac{1}{4} ]\times 0.430\\\\h_{L}= 0.1799 \times 62.9705 \times 0.430\\\\h_{L}=4.87\;W/m^2k$

Based on empirical correlation method, the average heat transfer coefficient for the plate is given by this equation:

$N_{uL}=\frac{h_{L}L}{k} =0.68 + \frac{0.670 R_{aL}^\frac{1}{4}}{[1+(\frac{0.492}{P_r})^\frac{9}{16}]^\frac{4}{19} } \\\\h_{L}=\frac{0.02699}{0.15} \times ( 0.68 + \frac{0.670 (1.48 \times 10^7)^\frac{1}{4}}{[1+(\frac{0.492}{0.7241})^\frac{9}{16}]^\frac{4}{19} })\\\\h_{L}=4.87\;W/m^2k$

Read more on heat transfer here: brainly.com/question/10119413

3 0

2 years ago

Yeah order for a firm voltage dividers to operate properly The load resistance value should be at least Times greater than resis

Svetlanka [38]

Answer:

A voltage divider is a simple series resistor circuit. It's output voltage is a fixed fraction of its input voltage. The divide-down ratio is determined by two resistors.

7 0

3 years ago

Explain race condition..don't spam..​

Explain race condition..don't spam..