Answer:
It will cost $68,620.5 to the club to add the grass turf to their field.
Explanation:
length of the field = l = 0.102 km = 0.102 × 1000 m
( 1km = 1000 m)
Width of the field w = 0.069 km = 0.069 × 1000 m
Area of the field , A= l × w
Cost of grass turfing = 
Cost of grass turfing on field of 
:
It will cost $68,620.5 to the club to add the grass turf to their field.
<span>convert grams to moles then use the equatino to do moles of Na to moles of H2O then convert moles of H2O to molecules by using avogadros number (6.022e23)
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The <span>epithelial hold the skin together.</span>
Here's the equation you use: Density = mass/volume
1) 5.2g/cm^3 = m/3.7cm^3
2) m = 5.2g/cm^3 x 3.7cm^3
3) m = 19.24g
You can check the answer by plugging it in
19.24g/3.7cm^3
= 5.2g/cm^3
Answer: 404.04 kJ.
Explanation:
To calculate the moles, we use the equation:
moles of 
According to stoichiometry :
2 moles of on burning produces = 1036 kJ
Thus 0.78 moles of on burning produces =
Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.
