Answer:4m/s ...for further explanation I've sent a photo for your refetence
Explanation:
The y-component of the velocity of the carrion is equal to zero. That being said, the time it takes for the carrion to reach the ground (as close as possible to the fox) can be calculated through the equation,
d = Vot + 0.5gt²
where d is the distance, Vo is initial velocity (in this case, zero), g is the acceleration due to gravity (9.8 m/s²). Substituting the known values,
14 = 0.5(9.8)(t²)
t = 1.69 seconds
Since the horizontal component of the velocity is 1.5 m/s, the distance from the base of the tree to the point where the carrion will fall is equal to,
(1.5 m/s)(1.69 s) = 2.535 m
We add this to the given distance of the fox from the base of the tree to determine the distance of the fox from the carrion.
total distance = 2.535 m + 7 m = 9.535 m
Given that the time it takes for it to travel would only be 1.69 seconds, the speed would then be,
speed = (9.535 m) / (1.69 s) = 5.64 m/s
<em>ANSWER: speed = 5.64 m/s</em>
Answer:
The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.
Explanation:
Let suppose that spaceship is accelerated uniformly. A yard equals 0.914 meters. A feet equals 0.304 meters. If air viscosity and friction can be neglected, then acceleration (), measured in meters per square second, is estimated by this kinematic formula:
(1)
Where:
- Travelled distance, measured in meters.
, - Initial and final speeds of the spaceship, measured in meters.
If we know that , and , then the acceleration experimented by the spaceship is:
The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.
Answer:
22m/s
Explanation:
Mass, m=60 kg
Force constant, k=1300N/m
Restoring force, Fx=6500 N
Average friction force, f=50 N
Length of barrel, l=5m
y=2.5 m
Initial velocity, u=0
Substitute the values
m
Work done due to friction force
We have
Substitute the values
Initial kinetic energy, Ki=0
Initial gravitational energy, \
Initial elastic potential energy
Final elastic energy,
Final kinetic energy,
Final gravitational energy,
Final gravitational energy,
Using work-energy theorem
Substitute the values