Question

The electron configuration of an element is 1s22s22p63s1. Describe what most likely happens when an atom of this element comes near an atom having seven valence electrons. Source stylesformat.

Answer 1

The element will lose it's valence electron (i.e 1 electron) to form ion when it comes close to an atom having 7 valence electrons.

The electronic configuration of the element is given below:

Electronic configuration => 1s² 2s²p⁶ 3s¹

From electronic configuration, we can see that the element has 1 valence electron.

This implies that the element will lose it's valence electron when it comes close to an atom having 7 valence electrons

This can further be seen as follow:

Electronic configuration of element => 1s² 2s²p⁶ 3s¹

Atomic number of element = 2 + 2 + 6 + 1 = 11

Name of element = sodium, Na

Element will 7 valence = chlorine, Cl

Na –> Na⁺ + e

Cl + e —> Cl¯

Na + Cl —> Na⁺ Cl¯

From the above illustration, we can see that the element (i.e Na) loses it's valence electron to form Na⁺ when it come close to Cl (having 7 valence electrons)

See attachment photo for further details

Learn more on group 1 and 7 elements: brainly.com/question/337107