The electron configuration of an element is 1s22s22p63s1. Describe what most likely happens when an atom of this element comes n
1 answer:
The element will lose it's valence electron (i.e 1 electron) to form ion when it comes close to an atom having 7 valence electrons.
The electronic configuration of the element is given below:
Electronic configuration => 1s² 2s²p⁶ 3s¹
From electronic configuration, we can see that the element has 1 valence electron.
This implies that the element will lose it's valence electron when it comes close to an atom having 7 valence electrons
This can further be seen as follow:
Electronic configuration of element => 1s² 2s²p⁶ 3s¹
Atomic number of element = 2 + 2 + 6 + 1 = 11
Name of element = sodium, Na
Element will 7 valence = chlorine, Cl
Na –> Na⁺ + e
Cl + e —> Cl¯
Na + Cl —> Na⁺ Cl¯
From the above illustration, we can see that the element (i.e Na) loses it's valence electron to form Na⁺ when it come close to Cl (having 7 valence electrons)
See attachment photo for further details
Learn more on group 1 and 7 elements: brainly.com/question/337107
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