Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
2 and 3 are prime numbers, so it means that the greatest common factor is:
G.C.M(2;3)=2*3=6
Answer:
Step-by-step explanation:
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Answer:
106+18≠28
106+18=124
in case the b was misplaced with the 6
10b=28-18
10b=10
10b/10=10/10
b=1
hope this is helpful
