Answer:
The pH of the buffer is 4.77
Explanation:
Using Henderson-Hasselbalch equation we can solve the pH of the buffer:
pH = pKa + log [A⁻] / [HA]
<em>Where pH is the pH of the buffer</em>
<em>pKa is -log Ka = 5.056</em>
<em>[A⁻] = [NaA] = 0.2M</em>
<em>[HA] = 0.39M</em>
<em />
Replacing:
pH = 5.056+ log [0.2] / [0.39]
pH = 4.77
<h3>The pH of the buffer is 4.77</h3>
<em />
Answer:
a) atoms Pb = 4.3595 E22 amu
b) g = ( 6.022 E23 amu ) × ( Mw )
Explanation:
sample:
∴ m = 15.00 g
a) atoms Pb = ?
⇒ atoms Pb = (15.00g Pb)(mol Pb/207.2 g)(6.022 E23 amu/mol)
⇒ atoms Pb = 4.3595 E22 amu
b) relationship:
∴ 1 mol (n) ≡ 6.022 E23 amu......(1)
∴ mass (g) ≡ (Mw)×(n)
⇒ n = g / Mw..........(2)
∴ Mw: molecular weight
(1) = (2):
⇒ g / Mw ≡ 6.022 E23 amu
⇒ g ≡ ( 6.022 E23 amu ) × ( Mw )
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Water contributes to the fitness of the environment to support life in several ways :
- Life on Earth began in water and evolved there for 3 billion years before colonizing the land.
- Even terrestrial organisms are tied to water.
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- Cells are about 70–95% water.
- Water is a reactant in many of the chemical reactions of life.
- Water is the only common substance that exists in the natural world in all three physical states of matter: solid ice, liquid water, and water vapour.
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- Water is unusual because it is less dense as a solid than as a cold liquid.
- Most materials contract as they solidify, but water expands.
- At temperatures above 4°C, water behaves like other liquids, expanding as it warms and contracting as it cools.
- Water begins to freeze when its molecules are no longer moving vigorously enough to break their hydrogen bonds.
- When water reaches 0°C, water becomes locked into a crystalline lattice, with each water molecule bonded to a maximum of four partners.
Learn more about Water here : brainly.com/question/5060579
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Answer:
742.2 L
Explanation:
First we must find the number of moles of nitroglycerine reacted.
Molar mass of nitroglycerine= 227.0865 g/mol
Mass of nitroglycerine involved = 1×10^3 g
Number of moles of nitroglycerine= 1×10^3g/227.0865 g/mol
n= 4.40361 moles
T= 1985°C + 273= 2258K
P= 1.100atm
R= 0.082atmLmol-1K-1
Using the ideal gas equation:
PV= nRT
V= nRT/P
V= 4.40361× 0.082× 2258/1.1
V= 742 L
Answer:
V = 94.24 cm3
Explanation:
Uranium metal has a very high density of 19.1 g/cm3.
d = 19.1 g/cm3
m = 1800 g
m = V × d
=> V = m/d = 1800/19.1 = 94.24 cm3
