Answer:
Hello There!!
Explanation:
When a metal reacts with oxygen gas metal oxide forms.Whenever a compound or element reacts with oxygen It turns to oxide.
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Acid palmitic acid has higher melting point, because it has two more methylene groups.
![\text { Myristic acid } \rightarrow \mathrm{CH}_3\left(\mathrm{CH}_2\right)_{12} \mathrm{COOH} \\& \text { Palmitic acid } \rightarrow \mathrm{CH}_3\left(\mathrm{CH}_2\right)_{14} \mathrm{COOH} \\](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Myristic%20acid%20%7D%20%5Crightarrow%20%5Cmathrm%7BCH%7D_3%5Cleft%28%5Cmathrm%7BCH%7D_2%5Cright%29_%7B12%7D%20%5Cmathrm%7BCOOH%7D%20%5C%5C%26%20%5Ctext%20%7B%20Palmitic%20acid%20%7D%20%5Crightarrow%20%5Cmathrm%7BCH%7D_3%5Cleft%28%5Cmathrm%7BCH%7D_2%5Cright%29_%7B14%7D%20%5Cmathrm%7BCOOH%7D%20%5C%5C)
Acid palmitic acid has higher melting point, because it has two more methylene groups.
Giving it a greater surface area and therefore more intermolecular van der waals interact than the myristic acid.
stearic arid ![\mathrm{CH}_3\left(\mathrm{CH}_2\right)_{16} \mathrm{COOH}](https://tex.z-dn.net/?f=%5Cmathrm%7BCH%7D_3%5Cleft%28%5Cmathrm%7BCH%7D_2%5Cright%29_%7B16%7D%20%5Cmathrm%7BCOOH%7D)
linoleic acid
(two double bond)
Stearic acid has higher Melting point, because it does not have any Carbon-Carbon double bonds, whereas linoleic acid has two cis double bonds which prevent the molecules from packing closely together.
Oleic Acid and Linoleic acid.
-one double bond (cis)
Acid palmitic acid has higher melting point, because it has two more methylene groups.
For more such question on methylene group.
brainly.com/question/4279223
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Answer: The initial temperature of the iron was ![515^0C](https://tex.z-dn.net/?f=515%5E0C)
Explanation:
![heat_{absorbed}=heat_{released}](https://tex.z-dn.net/?f=heat_%7Babsorbed%7D%3Dheat_%7Breleased%7D)
As we know that,
![Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})](https://tex.z-dn.net/?f=Q%3Dm%5Ctimes%20c%5Ctimes%20%5CDelta%20T%3Dm%5Ctimes%20c%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29)
.................(1)
where,
q = heat absorbed or released
= mass of iron = 360 g
= mass of water = 750 g
= final temperature = ![46.7^0C](https://tex.z-dn.net/?f=46.7%5E0C)
= temperature of iron = ?
= temperature of water = ![22.5^oC](https://tex.z-dn.net/?f=22.5%5EoC)
= specific heat of iron = ![0.450J/g^0C](https://tex.z-dn.net/?f=0.450J%2Fg%5E0C)
= specific heat of water= ![4.184J/g^0C](https://tex.z-dn.net/?f=4.184J%2Fg%5E0C)
Now put all the given values in equation (1), we get
![-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]](https://tex.z-dn.net/?f=-360%5Ctimes%200.450%5Ctimes%20%2846.7-x%29%3D%5B750%5Ctimes%204.184%5Ctimes%20%2846.7-22.5%29%5D)
![T_i=515^0C](https://tex.z-dn.net/?f=T_i%3D515%5E0C)
Therefore, the initial temperature of the iron was ![515^0C](https://tex.z-dn.net/?f=515%5E0C)