Explanation:
The answer would be B.
As paramagnetic with 3 unpaired electrons. Since there are 6 ligands around the Co+2 ion it isoctahedral and these ligands are neutral. This makes the overall charge on the complex +2 and therefore comes from the configuration for Co+2 which is [Ar] 3d7. Since it is in high spin you must fill all the orbitals with at least one electron and then pair up any that remain. If you do this, 3 unpaired electrons remain. Para magnetism occurs in substances with unpaired electrons.
It is actually a Colloid, which means it will never mix and settle.<span />
Answer:
Second step: 4-bromo-1-methyl-2-nitrobenzene.
Third step: 1.5-dibromo-2-methyl-3-nitrobenzene.
Explanation:
To solve this exercise I will use the concepts of electrophilic substitution. In these reactions, a functional group is displaced by an electrophile. In the attached image are the two main products.
Answer:
positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).
The charge of an ion of calcium that loses two electrons is D.) +2
hope this helps you
