Answer:
84 g of N₂
Explanation:
We begin from the reaction:
N₂O₄ + 2N₂H₄ → 3N₂ + 4H₂O
1st step: Find out the limiting reactant.
We convert the mass to moles.
276 g . 1mol/ 92g = 3 moles of N₂O₄
64 g . 1mol / 32g = 2 moles of hidrazine
Limiting reactant is the hydrazine. Ratio is 1:2, then for 3 moles of tetroixde I may need 6 moles of N₂H₄. (But I only have 2).
To determine the grams of produced nitrogen we see stoichiometry (2:3)
2 moles of hydrazine can produce 3 moles of N₂
Definetaly our 2 moles make 3 moles of gas.
We convert the moles to mass.
3 mol . 28g /1mol = 84 g of N₂
Answer:
10.87 g of Ethyl Butyrate
Solution:
The Balance Chemical Equation is as follow,
H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH → H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O
According to equation,
88.11 g (1 mol) Butanoic Acid produces = 116.16 g (1 mol) Ethyl Butyrate
So,
8.25 g Butanoic Acid will produce = X g of Ethyl Butyrate
Solving for X,
X = (8.25 g × 116.16 g) ÷ 88.11 g
X = 10.87 g of Ethyl Butyrate
Answer:
Explanation:
Dado que:
masa de oxígeno gaseoso = 100 g
presión = 1 atm
temperatura = 273 K
(a)
número de moles de oxígeno contenidos en el matraz = masa de oxígeno / masa molar de oxígeno
= 100 g / 16 gmol⁻¹
= 6.25 moles
(b) El número de moléculas de oxígeno es el siguiente:
Dado que 1 mol de oxígeno gaseoso contiene 6.023 * 10²³ moléculas de oxígeno.
Entonces, 6.25 moles contendrán:
= (6.25 × 6.023 * 10²³) moléculas de oxígeno.
≅ 3.764 × 10²³ moléculas de oxígeno.
(c) El número de átomos de oxígeno es:
= 2 × 3.764 × 10²³
= 7.528 × 10²³ átomos de oxígeno
(d) Usando la ecuación de gas ideal
PV = nRT
El volumen ocupado por el oxígeno =
Volumen ocupado por oxígeno =
Volumen ocupado por oxígeno= 14185.76 m³
Answer:
A.) DNA is a double helix, and RNA is a single strand.
C.) DNA is involved only in transcription, and RNA is involved in both transcription and translation.
E.) DNA does not have uracil as a nitrogen base, but RNA does have uracil as a nitrogen base.
Explanation:
Have a great rest of your day
#TheWizzer