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3 years ago

A 356.3 G rock is traveling at 14.2 m/s. How much kinetic energy in joules does it have?

Physics

1 answer:

geniusboy [140]3 years ago

3 0

Answer:

Ek=35.922J

Explanation:

Ek=0.5mv^2

Ek=0.5(0.3563kg)(14.2)^2

Ek=35.922J

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A bus is moving at a constant speed of 40 m/s. How many hours will it takes to travel 260 miles?

lawyer [7]

Explanation:

1 mile = 1609m

Distance=260 miles= 418340 m

Speed= 40 m/s

Time = distance/speed

= 418340/40

=10458.5 seconds

= 2.9 hours

8 0

3 years ago

A light-rail commuter train blows its 200 Hz horn as it approaches a crossing. The speed of sound is 339 m/s. (a) An observer wa

ddd [48]

Answer:

a) 30.82 m/s

b) 183.33 Hz

Explanation:

V = speed of the sound = 339 m/s

v = speed of the train = ?

f' = observed frequency by the observer = 220 Hz

f = actual frequency of the observer = 200 Hz

using the equation

$f' = \frac{fV}{V - v}$

$220 = \frac{(200)(339)}{339 - v}$

v = 30.82 m/s

V = speed of the sound = 339 m/s

v = speed of the train = 30.82 m/s

f'' = observed frequency by the observer as train moves away = ?

f = actual frequency of the observer = 200 Hz

using the equation

$f'' = \frac{fV}{V + v}$

$f'' = \frac{(200)(339)}{339 + 30.82}$

f'' = 183.33 Hz

3 0

3 years ago

Can anyone explain what weak force could do? I’ve been reading comics and I don’t understand what they can do when it says “they

Morgarella [4.7K]

Explanation:

To my understanding of comic books, weak force indicates that the hero was strong enough to overcome its powers...

4 0

4 years ago

The activation energy for the isomerization reaction of CH3NC in Problem 14 is 161 kJ mol 1, and the reaction rate constant at 6

astraxan [27]

Answer:

Explanation:

Below is an attachment containing the solution to the question.

5 0

3 years ago

A circular wire loop of radius LaTeX: RR lies in the xy-plane with the z-axis running through its center. There is initially no

frosja888 [35]

Answer:

Explanation:

Given a circular loop of radius R

r = R

Note: the radius lies in the xy plane

Area is given as

A = πr² = πR²

At t = 0, no magnetic field B=0

The magnetic field is given as a function of time

B = C•exp(t) •i + D•t² •k

Where C and D are constant

We want to find the magnitude of EMF in the circular loop.

EMF is given as

ε = - N•dΦ/dt

Where,

N is number of turn and in this case we will assume N = 1.

Φ is magnetic flux and it is given as

Φ = BA

ε = - N•d(BA)/dt

Where A is a constant, then we have

ε = - N•A•dB/dt

B = C•exp(t) •i + D•t² •k

dB/dt = C•exp(t) •i + 2D•t •k

Then,

ε = - N•A•dB/dt

ε = - 1•πR²•(C•exp(t) •i + 2D•t •k)

ε = -πR²•(C•exp(t) •i + 2D•t •k)

So, let find the magnitude of EMF

Generally finding magnitude of two vectors R = a•i + b•j

Then, |R| = √a² + b²

So, applying this we have,

ε = πR² (√(C²•exp(2t) + 4D²t²))

From the given magnetic field, we are given that,

B = 0 at t = 0

B = C•exp(t) •i + D•t² •k

B = 0 = C•exp(0) •i + D•0² •k

0 = C

Then, C = 0.

So, substituting this into the EMF.

ε = πR² (√(0²•exp(2t) + 4D²t²))

ε = πR² (√4D²t²)

ε = πR² × 2Dt

ε = 2πDR²t

So, the EMF is also a function of time

ε = 2πDR²t

4 0

4 years ago