What is the momentum of a 12 kg condor flying at 6 m/s?

9,10,and11 please I want the answer I can't found it

Ede4ka [16]

Q9. Inertia is the tendency of an object to resist any change in its motion.

Q10. A moving object's momentum depends on the object's mass and velocity.

Q11. I believe it would be air resistance. The fluid friction that opposes the motion of object's through the air.

7 0

3 years ago

If you travel from Yakima to Ellensburg (Yakima to Ellensburg is 50 miles) with a speed of 60 miles/hour for half of the

koban [17]

Answer:

$\displaystyle \frac{480}{7}\approx 68.6\; \rm mph$ .

Explanation:

The average speed of an object is equal to total distance over total time.

Distance traveled: $\rm 50 \; mi$ .

How much time is taken? This trip is divided into two halves, each of distance $\displaystyle \frac{50}{2} = 25\;\rm mi$ .

Time spent on the first half of the trip:

$\displaystyle t_1 = \frac{s_1}{v_1} = \frac{25}{60} = \frac{5}{12}\; \rm hours$ .

Similarly, time spent on the second half of the trip:

$\displaystyle t_2 = \frac{s_2}{v_2} = \frac{25}{80} = \frac{5}{16}\; \rm hours$ .

In total:

$\displaystyle \frac{5}{12} + \frac{5}{16} = \frac{35}{48} \; \rm hours$ .

Average speed:

$\begin{aligned} \text{Average speed} &= \frac{\text{Total Distance}}{\text{Total Time}}\\ &= 50 \left/\frac{35}{48}\right.\\ &= 50 \cdot \frac{48}{35} \\&= \frac{480}{7}\approx 68.6\; \rm mph \end{aligned}$ .

This value turned out to be slightly different from the average of the speed during the two halves of the journey. The reason is that the object traveled at each speed for a different amount of time. It spent more time at the slower speed, which gives that speed a greater weight in the average. That explains why the average speed is closer to $\rm 60\; mph$ rather than $\rm 80\; mph$ .

3 0

3 years ago

a 2.0 kg ball is dropped from a height of 20 m onto a soft surface and rebounds to a height of 5.0 m . what is the magnitude of

Yuki888 [10]

Based on the data provided, the impulse of the floor on the ball is 59.4 Ns.

<h3>What is the impulse of the floor on the ball?</h3>

Using the equation of motion to determine the velocity at the end of the fall

v^2 = u^2 + 2gh

Where v is velocity at the end of fall

u is initial velocity = 0

g is acceleration due to gravity = 9.81 m/s^2

h is height = 20

Taking downward velocity as negative and up as positive

v^2 = 0 + 2 (9.81)(20)

v^2 = 392.4

v = - 19.8 m/s

The velocity, v after bouncing is calculated also:

u = 0

g = 9.81 m/s^2

h = 5.0 m

v^2 = 0 + 2(9.81)(5)

v^2 = 98.1

v = 9.904 m/s

Impulse = change in momentum
Impulse = m(v- u)

Impulse = 2.0 × (9.9 -(-19.8)

Impulse = 59.4 Ns

Therefore, the impulse of the floor on the ball is 59.4 Ns.

Learn more about impulse at: brainly.com/question/904448

5 0

2 years ago

Why is food considered “potential energy” even though it does not have mass suspended in air?

LekaFEV [45]

Answer:

Food is potential energy because as our bodies digest it then the stored energy will turn into energy that helps us to move and grow

Explanation:

i hope this helps

3 0

2 years ago

Read 2 more answers

Madison pushes with a 210-N horizontal force on a 24-kg crate of coffee resting on a warehouse floor. The force of friction on t

kotykmax [81]

Answer:

5.7 m/s^2

Explanation:

First of all, we need to calculate the resultant force on the crate. We have:

- A force of +210 N in the positive direction

- The frictional force of -74 N in the opposite direction

So, the resultant force is

F = 210 N - 74 N= 136 N

So now we can apply Newton's second law to find the acceleration:

$F=ma$

where m=24 kg is the mass of the crate. Re-arranging the equation, we get:

$a=\frac{F}{m}=\frac{136 N}{24 kg}=5.7 m/s^2$

5 0

3 years ago