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IRISSAK [1]
4 years ago
11

Part a write an equation for the formation of nh3(g) from its elements in its standard states. express your answer as a chemical

equation. identify all of the phases in your answer. submitmy answersgive up part b find δh∘f for nh3(g) from appendix iib in the textbook. express your answer using three significant figures. δh∘f = kj/mol submitmy answersgive up part c write an equation for the formation of co2(g) from its elements in its standard states. express your answer as a chemical equation. identify all of the phases in your answer. submitmy answersgive up part d find δh∘f for co2(g) from appendix iib in the textbook. express your answer using four significant figures. δh∘f = kj/mol submitmy answersgive up part e write an equation for the formation of fe2o3(s) from its elements in its standard states. express your answer as a chemical equation. identify all of the phases in your answer. submitmy answersgive up part f find δh∘f for fe2o3(s) from appendix iib in the textbook. express your answer using four significant figures. δh∘f = kj/mol submitmy answersgive up part g write an equation for the formation of ch4(g) from its elements in its standard states. express your answer as a chemical equation. identify all of the phases in your answer. submitmy answersgive up part h find δh∘f for ch4(g) from appendix iib in the textbook. express your answer using three significant figures.
Chemistry
2 answers:
pochemuha4 years ago
8 0
Sourse 

https://quizlet.com/19584916/chemistry-chapter-6-and-7-flash-cards/
andrey2020 [161]4 years ago
3 0
A. N₂ (g) + 3 H₂ (g) --> 2 NH₃ (g)
B. The value for standard enthalpy of formation is empirical given that the reactants involved were pure elements. So, you can search this on the internet or in any textbook. The Hf for NH₃ is -46.0 kJ/mol.
C. C (s) + O₂ (g) --> CO₂ (g)
D. The Hf for CO₂ is <span>-393.5 kJ/mol
E. 4 Fe (s) + 3 O</span>₂ (g) --> 2 Fe₂O₃ (s)
F. The Hf for solid Fe₂O₃ is -826.0 kJ/mol.
G. C (s) + 2 H₂ (g) --> CH₄ (g)
H. The Hf for methane gas is -74.9 kJ/mol.
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What is the easiest way to explain molecular compounds and covalent bonds also adding information about valance electrons?
wlad13 [49]

Answer:

Molecular compounds consist of two or more nonmetals. The nonmetals that make up a molecular compound are held together by covalent/molecular bonds. Covalent bonds is known as the "sharing" of valence electrons between two or more chemical species. Valence electrons are shared so that the atoms of the compound can become stable, much like how ionic bonds transfer valence electrons between atoms to achieve stability.

5 0
3 years ago
What is the new mass/volume percent (m/v) of a KOH solution that is prepared by diluting 110 mL of a 6.0% (m/v) KOH solution to
denis-greek [22]

Answer:

The new mass/volume percent is 2.0% (m/v)

Explanation:

Dilution is a procedure by which the concentration of a solution is decreased, generally with the addition of a diluent. In other words, dilution is a process in which a concentrated solution is always started, to which a greater volume of solvent is added, causing the concentration and volume of the resulting solution to change. But the amount of solute used to prepare the initial solution remains the same.

The calculation of a dilution is made by:

Cinitial. Vinitial = Cfinal. Vfinal

where C indicates concentration and V indicates volume.

In this case:

  • Cinitial: 6.0% (m/v)
  • Vinitial: 110 mL
  • Cfinal: ?
  • Vfinal: 330 mL

Replacing:

6.0% (m/v) * 110 mL= Cfinal* 330 mL

Solving:

Cfinal=\frac{ 6.0 (m/v)*110 mL}{330 mL}

Cfinal=   2.0% (m/v)

<u><em>The new mass/volume percent is 2.0% (m/v)</em></u>

4 0
3 years ago
How many liters are in 555 g of O2
victus00 [196]

Answer:

388.5

Explanation:

\frac{555}{32}  = 17.34375 \\ 17.34375  \times 22.4 = 388.5

3 0
4 years ago
A certain reaction has an activation energy of 67.0 kJ/mol and a frequency factor of A1 = 4.20×1012. What is the rate constant,
MrRa [10]

Answer:

  • K = 7.00

Explanation:

<u>1) Arrhenius equation</u>

Arrhenius equation shows the relation between activation energy, temperature, and the equilibrium constant.

This is the equation:

       K=Ae^{-Ea/RT}

Where:

  • K is the equilibrium constant,
  • A is the frequency factor,
  • Ea is the activation energy (in J/mol),
  • T is the temperature in kelvins (K), and
  • R is the universal constant.

<u></u>

<u>2) Substitute, using the right units, and compute:</u>

  • A = 4.20 × 10¹² (dimensionless)
  • Ea = 67.0 kJ/mol = 67,000 J/mol
  • T = 24.0°C = 24.0 + 273.15 K = 297.15 K
  • R = 8.314 J/K mol

K=Ae^{-Ea/RT}=(4.20)(10)^{12}e^{-67,000J/mol/(8.314J/molK.297.15K)}

  • K = 7.00
5 0
3 years ago
Water, also known as H2O, cannot be separated into hydrogen and oxygen.
Dmitry [639]

Answer:

So, H2O means two atoms of hydrogen mixed with one atom of oxygen. All pure water is the same, two parts hydrogen to one part oxygen. ... Water cannot be separated by any physical means.

Explanation:

Logic and my notes from chem....

6 0
3 years ago
Read 2 more answers
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