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sergiy2304 [10]
2 years ago
5

16. A solution is made by dissolving 25 g of NaCl in enough water to make 1.0 L of solution. Assume the density of the solution

is 1.0 g/cm3. Calculate the molarity and molality of the solution.
Chemistry
1 answer:
nata0808 [166]2 years ago
4 0

Answer:

The molarity will be "0.43 M" and molality will be "0.43 m".

Explanation:

Given that:

mass of NaCl,

= 25 g

Volume of solution,

= 1 L

Density of solution,

= 1 gm/cm³

Now,

The weight of solvent will be:

= Volume\times density

= 1\times 1

= 1 \ kg

The mole of NaCl will be:

= \frac{mass}{Molar \ mass}

= \frac{25}{58.44}

= 0.43

hence,

The molarity will be:

= \frac{number \ of \ mole}{Volume \ of \ solution}

= \frac{0.43}{1}

= 0.43 \ M

The molality will be:

= \frac{mole \ of \ solute}{Weight \ of \ solvent}

= \frac{0.43}{1}

= 0.43 \ m

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