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r-ruslan [8.4K]
2 years ago
10

While hiking last year, Mike saw a large boulder next to a mountain trail. The boulder had no cracks. While hiking on the trail

this year, he saw two large cracks in the boulder.
Which of the following most likely caused these cracks to form?
Shaking from high winds.
Pressure from flowing water.
Erosion due to falling rain and snow.
Weathering due to freezing and thawing.
Plis
Chemistry
1 answer:
sesenic [268]2 years ago
3 0

Answer: weathering due to freezing and thawing

Explanation:

The reason that caused these cracks to form is weathering due to freezing and thawing.

Weathering simply means the breaking down of rocks. In this situation, the boulder is freezed and thawed and due to this, as time progresses, it'll gradually be broken down. This is the reason why Mike saw the cracks even though there were no cracks the last time he went hiking.

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anastassius [24]
<h3>Answer:</h3>

0.50 mol SiO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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<u>Chemistry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

30 g SiO₂ (sand)

<u>Step 2: Identify Conversions</u>

Molar Mass of Si - 28.09 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of SiO₂ - 28.09 + 2(16.00) = 60.09 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 30 \ g \ SiO_2(\frac{1 \ mol \ SiO_2}{60.09 \ g \ SiO_2})
  2. Multiply/Divide:                  \displaystyle 0.499251 \ mol \ SiO_2

<u>Step 4: Check</u>

<em>Follow sig figs and round. We are given 2 sig figs.</em>

0.499251 mol SiO₂ ≈ 0.50 mol SiO₂

5 0
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makkiz [27]

Answer:

Percent yield of SiC is 77.0%.

Explanation:

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So, 100.0 kg of SiO_{2} = \frac{100.0\times 10^{3}}{60.08} moles of SiO_{2} = 1664 moles of SiO_{2}

According to balanced equation, 1 mol of SiO_{2} produces 1 mol of SiC

Therefore, 1664 moles of SiO_{2} produce 1664 moles of SiC

Mass of 1664 moles of SiC = (1664\times 40.11)g = 66743g = 66.74 kg (4 sig. fig.)

Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)]\times 100%

                                 = \frac{51.4kg}{66.74kg}\times 100 %

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<h3>What is Kb?</h3>

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