To Calculate Velocity and Average Velocity you can use the same formula as both.
1 answer:
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Answer:
x = 0.176 m
Explanation:
For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.
Let's use trigonometry to decompose the tension
sin 60 = / T
T_{y} = T sin 60
cos 60 = Tₓ / T
Tₓ = T cos 60
we apply the equation
∑ τ = 0
-W L / 2 - w x + T_{y} L = 0
the length of the bar is L = 6m
-Mg 6/2 - m g x + T sin 60 6 = 0
x = (6 T sin 60 - 3 M g) / mg
let's calculate
let's use the maximum tension that resists the cable T = 900 N
x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)
x = (4676 - 5880) / 6860
x = - 0.176 m
Therefore the block can be up to 0.176m to keep the system in balance.
The magnitude of the electrostatic force is 0.09 N, and the force is attractive
Explanation:
The strength of the electrostatic force acting on a charged particle is given by
where
q is the charge
E is the magnitude of the electric field
For the charge in this problem, we have:
is the electric field
is the charge
Therefore, the force experienced by this charge is
And the negative sign means that the force is attractive: in fact, the charge is negative, while the charge that is producing the field is positive (because the electric field points outward), therefore the negative charge is attracted towards the positive charge that is generating the field.
Learn more about electrostatic force:
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