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3 years ago

To Calculate Velocity and Average Velocity you can use the same formula as both.

Physics

1 answer:

Elanso [62]3 years ago

4 0

Answer:

I believe it's True! Brainliest??

Explanation: Hope you have a great day :)

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Is the volume of a solid definite or indefinite?

FinnZ [79.3K]

A solid has a definite meaning that there is only one shape there can be meaning a solid has a definite volume

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4 years ago

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3 years ago

Read 2 more answers

A 15-foot ladder is leaning against a house with the base of the ladder 4 feet from the house. How high up the house does the la

eimsori [14]

Answer:

height of house to ladder reach is 14 ft

Explanation:

Given data

ladder = 15 ft

base = 4 ft

to find out

height of house

solution

we know this is triangle shape so we apply here

so we consider here x is ladder and y is base and z is height

by pythagoras theorem

z² + y² = x²

so here

z² = x² -y²

put value

z² = 15² - 4²

z² = 209

z = 14.45 = 14

so height of house to ladder reach is 14 ft

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3 years ago

Derek and Diane race each other on bicycles. Derek starts 4 seconds before Diane. He goes at a steady speed of 6 m/s. Diane star

ser-zykov [4K]

a. $x(t) = vt' = v(t+4) = 6(t+4) [m]$

Let's call:

$t$ the time calculated from the moment Diane starts her motion and $t'$ the time calculated from the moment Derek starts his motion. Derek starts his motion 4 seconds before Diane: this means that has an "advantage" of 4 seconds, so we can write

$t'=t+4$

Then:

$v=6 m/s$ is the uniform speed of Derek

Derek is moving in a uniform motion, so Derek's position will be given by (assuming that the starting position is zero):

$x(t) = vt' = v(t+4) = 6(t+4) [m]$

We see that this is correct: in fact, when t=0 (instant when Diane starts her motion), Derek has already travelled for

$x(t=0)=v(0+4)=6 (4)=24 m$

b. $x'(t)= \frac{1}{2}at^2 =\frac{1}{2}(2)t^2=t^2 [m]$

t is the time calculated from the moment Diane starts her motion. Diane is moving by accelerated motion, with constant acceleration $a=2 m/s^2$ and initial velocity $v_0=0$ , so its position at time t is given by the law of uniform accelerated motion: