Answer:
b it increases from left to right of the group and it decreases down the period.
Answer: 448 mL of hydrogen gas.
Solution:

Now,according to reaction
1 mole of magnesium produces one mole of hydrogen gas.
Then 0.020 moles of magnesium will produce 0.020 moles of hydrogen gas.
Moles of
gas : 0.020 mol
At STP, 1 mol of gas occupies 22.4 L
So volume of 0.020 mol of
produced at STP :
= 22.4/times 0.020 = 0.448 L = 448 mL (1L=1000mL)
The balanced chemical reaction is:
2KClO3 ----> 2KCl + 3O2
We are given the amount of oxygen gas to be produced from potassium chlorate. This will be the starting point for the calculations.
28.0 L O2 ( 1 mol / 22.4 L) (2 mol KClO3 / 3 mol O2) ( 122.55 g / 1 mol) = 102.13 g KClO3 is needed
Soap solution with 9 acidic
<span><span>Argon,</span><span>Carbon dioxide,</span><span>Neon,</span><span>Helium, and </span><span>Methane</span></span>