A 300 gg bird flying along at 5.7 m/sm/s sees a 10 gg insect heading straight toward it with a speed of 29 m/sm/s (as measured b
1 answer:
Answer:
bird's speed = 4.58 m/s
Explanation:
given data
mass of bird mb = 300 g
velocity of bird vb = 5.7 m/s
mass of insect mi = 10 g
velocity of insect vi = - 29 m/s
solution
here momentum of system is constant
we apply here conservation of momentum so
mb × v + mi × v = mb × vb + mi × vi ....................1
v ( mb + mi ) = mb × vb + mi × vi
put here value and we get
v ( 300 + 10 ) = { 300 × 5.7 } + { 10 × (-29) }
v =
v = 4.58 m/s
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<h2>QUESTION:- </h2>
➜what is kepler's law??
Kepler gave the three laws or theorems of motion of the orbitals bodies
This law state that the celestial bodies revolves around the stars in elliptical orbit and star as a single focus.
Example :- Earth revolves around the Sun as assuming it as single focus
This also shows that earth revolves around the sun in elliptical orbit.
Area covered by the planet is equal in equal duration of time irrespective of the position of the planet.
It also states that Angular momentum is constant
As Angular momentum is constant it means areal velocity is also constant.
where:-
A is the area.
T is the time.
L is the angular momentum.
M is the mass of the body.
square of the time of the revolution is directly proportional to the cube of the distance between the planet and star in Astronomical unit.
where:-
T = time of revolution
a is the distance between the planet and star.
Answer:
23
21.7391304348 m
Explanation:
L = Initial length = 500 m
= Change in temperature = 40-(-35)
= Coefficient of thermal expansion =
Change in length is given by
The change in length is 0.45 m
The number of joints would be
The number of joints is 23
Each bridge section length would be
The length of each bridge section would be 21.7391304348 m