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anastassius [24]
3 years ago
6

1. A race car moves along a circular track of radius 100m at a velocity of 25m/s. (a) What is

Physics
1 answer:
goldenfox [79]3 years ago
6 0

Given :

A race car moves along a circular track of radius 100m at a velocity of 25m/s.

To Find :

(a) What is  the time taken to complete one lap of the circular track.

(b) What is the time taken for 10  laps.

Solution :

Circumference of circular track,

C = 2\pi r\\\\C = 2\times \pi \times 100\ m\\\\C = 628.32 \ m

a) Time taken to complete one lap is :

t= \dfrac{628.32}{25}\ s\\\\t =25.13 \ s

b) Time taken to complete 10 laps is :

t_{10} = 10\times t\\\\t_{10} = 10\times 25.13\ s\\\\t_{10} = 251.3\ s

Hence, this is the required solution.

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A net force of 16 N causes a mass to accelerate at a rate of 5 m/s^2. Determine the mass.
Gnom [1K]

Answer:

So mass of the object will be 3.2 kg

Explanation:

We have net force on the object F = 16 N

Acceleration of the object a=5m/sec^2

We have top find the mass of the object

From newton law of motion we know that force is given by

F = ma , here m is mass and a is acceleration

So 16=5\times m

m=3.2kg

So mass of the object will be 3.2 kg

3 0
3 years ago
Enlight the contribution of science and technology for current pandemic of Corona virus??​
Tju [1.3M]

The vaccine ofcourse. They helped in making the vaccine.

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3 years ago
A 4.0-m-diameter playground merry-go-round, with a moment of inertia of
HACTEHA [7]

Answer:

7.1 ms⁻¹

Explanation:

d = diameter of merry-go-round = 4 m

r = radius of merry-go-round = \frac{d}{2} =  \frac{4}{2} = 2 m

I = moment of inertia = 500 kgm²

w_{i} = angular velocity of merry-go-round before ryan jumps = 2.0 rad/s

w_{f} = angular velocity of merry-go-round after ryan jumps = 0 rad/s

v = velocity of ryan before jumping onto the merry-go-round

m = mass of ryan = 70 kg

Using conservation of angular momentum

Iw_{i} - m v r = (I + mr^{2})w_{f}

(500)(2.0) - (70) v (2) = (I + mr^{2})(0)

1000 = 140 v

v = 7.1 ms⁻¹

5 0
3 years ago
S Problem Set<br> 2.) 6.4 x 109 nm to cm
anyanavicka [17]

Answer:

6.4\cdot 10^2 cm

Explanation:

First of all, let's convert from nanometres to metres, keeping in mind that

1 nm = 10^{-9} m

So we have:

6.4\cdot 10^9 nm \cdot 10^{-9} m/nm = 6.4 m

Now we can convert from metres to centimetres, keeping in mind that

1 m = 10^2 cm

So, we find:

6.4 m \cdot 10^2 cm/m = 6.4\cdot 10^2 cm

8 0
3 years ago
"Which of the following best describes the circuit shown below?
Anettt [7]
The figure shown above is series combination as the two resistors (bulb) are there which are then connected to the battery
so i conclude from the above options given the option  is B
hope it helps
3 0
3 years ago
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