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3 years ago

1. A race car moves along a circular track of radius 100m at a velocity of 25m/s. (a) What is

Physics

1 answer:

goldenfox [79]3 years ago

6 0

Given :

A race car moves along a circular track of radius 100m at a velocity of 25m/s.

To Find :

(a) What is the time taken to complete one lap of the circular track.

(b) What is the time taken for 10 laps.

Solution :

Circumference of circular track,

$C = 2\pi r\\\\C = 2\times \pi \times 100\ m\\\\C = 628.32 \ m$

a) Time taken to complete one lap is :

$t= \dfrac{628.32}{25}\ s\\\\t =25.13 \ s$

b) Time taken to complete 10 laps is :

$t_{10} = 10\times t\\\\t_{10} = 10\times 25.13\ s\\\\t_{10} = 251.3\ s$

Hence, this is the required solution.

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xxMikexx [17]

<span>The speed of a wave, V, is f *lambda. Where f is the frequency and lambda is the distance. If a new crest reaches the end every 4 secs; it takes 8s to cover the distance. Hence, f, which is the number of oscillations covered is 8s. So we have V = 8 * 5 = 40 ms^1.</span>

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3 years ago

A man pushes a lawn mower on a level lawn with a force of 195 N. If 37% of this force is directed downward, how much work is don

densk [106]

Answer:

$W = 1032.6 J$

Explanation:

Net force by which man push the lawn mower is given as

$F = 195 N$

now it is given that 37% of this force is vertically downwards

so we will have

$F_y = 0.37 \times 195$

$F_y = 72.15 N$

now we also know that

$F_x^2 + F_y^2 = F^2$

here we have

$F_x^2 + 72.15^2 = 195^2$

$F_x = 181.2 N$

Now work done by this force to move the lawn mower is given as

$W = F_x . d$

$W = (181.2)(5.7 m)$

$W = 1032.6 J$

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3 years ago

A 7.2 magnitude earthquake, with an epicenter in Northern Mexico, was felt over 100 miles away in Southern California because wa

ryzh [129]

Answer:

because waves generated

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1 year ago

Explain Archimedes Principle

rusak2 [61]

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces. Archimedes' principle is a law of physics fundamental to fluid mechanics. It was formulated by Archimedes of Syracuse.

Explanation:

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2 years ago

If he leaves the ramp with a speed of 31.0 m/s and has a speed of 29.5 m/s at the top of his trajectory, determine his maximum h

raketka [301]

Answer:

The maximum height reached is 4.63 m.

Explanation:

Given:

Initial speed of the man (u) = 31.0 m/s

Speed at the top of trajectory ( $u_x$ ) = 29.5 m/s

Acceleration due to gravity (g) = 9.8 m/s²

When the man reaches the top of the trajectory, the vertical component of velocity becomes zero and hence only horizontal component of velocity acts on him.

Also, since there is no net force acting in the horizontal direction, the acceleration is zero in the horizontal direction from Newton's second law. Thus, the horizontal component of velocity always remains the same.

So, speed at the top of trajectory is nothing but the horizontal component of initial velocity.

Now, initial velocity can be rewritten in terms of its components as:

$u^2=u_x^2+u_y^2$

Where, $u_x\ and\ u_y$ are the initial horizontal and vertical velocities of the man.

Now, plug in the given values and simplify. This gives,

$(31.0)^2=(29.5)^2+u_y^2\\\\961=870.25+u_y^2\\\\u_y^2=961-870.25\\\\u_y^2=90.75\ m^2/s^2--------1$

Now, we know that, for a projectile motion, the maximum height is given as:

$H=\frac{u_y^2}{2g}$

Plug in the value from equation (1) and 9.8 for 'g' to solve for 'H'. This gives,

$H=\frac{90.75}{2\times 9.8}\\\\H=4.63\ m$

Therefore, the maximum height reached is 4.63 m.

3 0

3 years ago