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zubka84 [21]
2 years ago
9

Which one does not share the same properties as the other

Chemistry
1 answer:
myrzilka [38]2 years ago
5 0

Answer:

Ti

Explanation:

Ti is titanium and does not share any similar properties with the likes of Si, silicon and At, astatine.

  • Titanium is a transition metal and a solid.
  • Silicon and Astatine are non - metals.
  • Silicon and Astatine also belongs to the p-block on the periodic table whereas Titanium is found on the d-block.
  • Silicon and Astatine would prefer to take part in reactions where they can gain electrons because they are non metals whereas Titanium due to its metallic property would prefer a reaction where it can lose electrons.

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WILL GIVE BRAINLIEST, Which of the following would have the greatest amount of surface area?
Elodia [21]

Answer:

C. 1 cubic foot of loose sand

Explanation:

For many  objects having equal volume , surface area will be maximum

of the object which has spherical shape .

But when a sphere is broken into tiny small spheres , total surface area of all the small spheres will be more than surface area of big sphere .

Hence among the given option , surface area of loose sand will have greatest surface area . Loose sand is equivalent to small spheres .

5 0
3 years ago
What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?
Sergeu [11.5K]

Answer:

\large \boxed{\text{b. 1.5 h}}

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463  h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}

4 0
3 years ago
Although Rutherford is credited with the famous gold foil scattering experiment, he didn’t actually conduct this experiment hims
DerKrebs [107]
If he was the primary scientist doing it as he did alot of the heavy lifting then yes its ok, but i also think how the others should also me at least mentioned. Or they could just not name the experiment by a person just so its not too biased
3 0
3 years ago
a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. when placed in water, the block sinks
Art [367]

 When the block  of iron is  placed  in water  the volume of water that   is  displaced is  27.0  cm³


  <u><em> calculation</em></u>

The  volume water that is displaced is equal to volume of block  of the iron


volume of block of iron = length x width x height

   length= 3 cm

   width = 3  cm

 height = 3 cm

volume  is therefore = 3 cm  x  3 cm x  3  cm = 27  cm³   therefore the volume displaced  = 27 cm³  since the volume of water displaced  is equal to  volume of block.

3 0
3 years ago
Read 2 more answers
!!!Need answer for chem homework ASAP PLS !!!!
stealth61 [152]

Answer:

The answer to your question is: kc = 6.48

Explanation:

Data

             Given                 Molecular weight

CaO =    44.6 g                    56 g

CO₂ =     26 g                       44 g

CaCO₃ = 42.3 g                  100 g

Find moles

        CaO                 56 g ----------------  1 mol

                                 44.6 g --------------   x

                               x = (44.6 x 1) / 56 = 0.8 mol

        CO₂                 44 g -----------------  1 mol

                                26 g ----------------    x

                               x = (26 x 1 ) / 44 = 0.6  moles

        CaCO₃            100 g ---------------   1 mol

                                42.3g --------------    x

                              x = (42.3 x 1) / 100 = 0.423 moles

       

Concentrations

 

        CaO     =    0.8 / 6.5  = 0.12 M

         CO₂    =     0.6 / 6.5 = 0.09 M

        CaCO₃  =   0.423 / 6.5 = 0.07 M

Equilibrium constant =   \frac{[products]}{[reactants]}

Kc = [0.07] / [[0.12][0.09]

Kc = 0.07 / 0.0108

kc = 6.48

7 0
3 years ago
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