Answer:
8. the answer is B.
9. the answer is A.
Explanation:
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8. In this case, by bearing to mind that the limiting reactant is always completely consumed and the excess one remain as a leftover at the end of the reaction, we can also infer that as all the limiting reactant is consumed, it must determine the maximum amount of product as the excess reactant will hypothetically produce a greater mass than expected; thus, the answer to this question is B.
9. In this case, since the mole ratio of oxygen to water is 1:2, the following proportional factor is used to calculate the produced mass of water:

Thus, the answer is this case is A.
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If he was 30.8% too low, it means that he was at 69.2% of the boiling point needed. So 50o C is 69.2% of total.
In order to know what 100% is, you can divide the number by it's percentage and then multiply it by a hundred.
So: 50/30.8=1.623
1.623*100=162.3
So the correct boiling point of the liquid he was working with in the lab is 162.3 oC
Answer:
Covalent bonds.
Explanation:
Covalent bonds are intermolecular bonds which involve the sharing of electrons between atoms or molecules and ions with close or near electronegativity values.
This usually form molecules. This is also the sharing of electrons donated by one of the atoms or by both of the atoms to form a molecule and at the same time obtain a stable octet state.
Answer:
Three Na atom(s) each lose one electron, forming three Na+ ions. One N atom gains three electrons, forming a N^-3 ion. The ions attract, forming Na3N
Explanation:
Three Na atom(s) each lose one electron, forming three Na+ ions. One N atom gains three electrons, forming a N^-3 ion. The ions attract, forming Na3N.
Ionic bond:
It is the bond which is formed by the transfer of electron from one atom to the atom of another element.
Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.
For example:
Na₃N is ionic compound. The electronegativity of is 3.04 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the nitrogen. Sodium becomes positive and nitrogen becomes negative ion.
One nitrogen atom required three electrons to complete the octet while sodium have one valance electron that's why three sodium atoms combine with one nitrogen atom.
The given question is incomplete. The complete question is ;
Ammonia gas can be prepared by the following reaction:

In an experiment, 27.6 g of ammonia gas,
, is produced when it was predicted that 50.2 g of
would form.
What is the theoretical yield of
? What is the actual yeild of
? What is the percent yeild of
?
Answer: a) 50.2 g
b) 27.6 g
c) 5.0 %
Explanation:
a) Theoretical yield is defined as the amount of the product that is possible in the reaction.
Theoretical yield of
= 50.2 g
b) Experimental or actual yield is defined as the amount of the product that is actually formed in the reaction.
Experimental yield of
= 27.6 g
c) Percentage yield is defined as the ratio of experimental yileld to the theoretical yield in terms of percentage.


Hence percentage yield for the reaction is 55.0 %.