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Free_Kalibri [48]
3 years ago
7

2. List three types of chemical changes. Help me

Chemistry
1 answer:
Sedaia [141]3 years ago
6 0
Burning wood, rusting of iron, and baking a cake
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PLEASE HELP ASAP Do NOT give me a random gibberish answer or else I might report you!!
Veronika [31]

Answer:

Physical Changes:

Let's say during your camping trip you stepped on a twig. This would be a physical change.

Let's also say that while there, you accidentally stepped on a flower, causing it to fall off of it's stem. This would also be a physical change.

Chemical Changes:

Let's say you start a fire using wood that you got from this rainforest. Since the act of burning something is a chemical change, this would apply.

Let's also say you forget a banana peel there. After a while, it would start to rot. And since rotting is a chemical change, this would apply as well.

Explanation:

Hope this helps!

8 0
3 years ago
A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0
4 years ago
Complete the table by writing correct formulas for the compounds formed by combining positive and negative ions. then name each
Gwar [14]
NH₄NO₃ - ammonium-nitrate.
(NH₄)₂CO₃ - ammonium carbonate.
NH₄CN - ammonium cyanide.
(NH₄)₃PO₄- ammonium phosphate.
Sn(NO₃)₄ - tin(IV) nitrate.
Sn(CO₃)₂ - tin(IV) carbonate.
Sn(CN)₄ - tin(IV) cyanide.
Sn₃(PO₄)₄ - tin(IV) phosphate.
Fe(NO₃)₃ - iron(III) nitrate.
Fe₂(CO₃)₃ - iron(III) carbonate.
Fe(CN)₃ - iron(III) cyanide.
FePO₄ - iron(III) phosphate.
Mg(NO₃)₂ - magnesium nitrate.
MgCO₃ - magnesium carbonate.
Mg(CN)₂ - magnesium cyanide.
Mg₃(PO₄)₂ - magnesium phosphate.
4 0
3 years ago
How many electrons does the 2nd main energy level hold when it is full?
UNO [17]

Answer:

8 electrons

Each principal energy level can contain up to 2n2 electrons, where n is the number of the level. Thus, the first level can contain up to 2 electrons, 2(12) = 2; the second up to 8 electrons, 2(22) = 8; the third up to 18, 2(32) = 18; and so on.

Explanation:

5 0
3 years ago
Identify the titration curve for a monoprotic weak acid titrated with a strong base.
ahrayia [7]

Answer:

Titration is a technique to determine the concentration of an unknown solution. As illustrated in the titration setup above, a solution of known concentration (titrant) is used to determine the concentration of an unknown solution (titrand or analyte).

Typically, the titrant (the solution of known concentration) is added through a burette to a known volume of the analyte (the solution of unknown concentration) until the reaction is complete. Knowing the volume of titrant added allows us to determine the concentration of the unknown analyte. Often, an indicator is used to signal the end of the reaction, the endpoint. Titrant and analyte is a pair of acid and base. Acid-base titrations are monitored by the change of pH as titration progresses.

Let us be clear about some terminologies before we get into the discussion of titration curves.

7 0
3 years ago
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