Explanation:
Percentage ethylene by weight = 57%
Percentage propylene by weight = 43%
Suppose in 100 grams of polymer:
Mass of ethylene = 57 g
Mass of propylene = 43 g
Moles of ethylene = 
Moles of propylene = 
1 mole = 
molecules/ atoms
Units of ethylene = 
Units of propylene = 
a) Fraction of ethylene units:
b ) Fraction of propylene units:
Answer:
Bases do not react with metals in the way that acids do
Explanation:
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Answer:
The concentration the student should write down in her lab is 2.2 mol/L
Explanation:
Atomic mass of the elements are:
Na: 22.989 u
S: 32.065 u
O: 15.999 u
Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.
Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.
For mole(s) of Na2S2O3 = (mass taken)/(molar mass)
= (17.240 g)/(158.105 g/mol) = 0.1090 mole.
Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)
= 0.05029 L.
To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:
= (moles of sodium thiosulfate)/(volume of solution in L)
= (0.1090 mole)/(0.05029 L)
= 2.1674 mol/L
The hybridization for C in acetylene, HCCH, or C₂H₂ is 'sp'.
Discussion:
There are three different forms of hybridization -
- sp- The first occurs when two carbon atoms are triple linked.
- sp₂- When two carbon atoms are double-bonded to one another, this is known as sp₂.
- sp₃- When a single bond joins two carbon atoms, this is known as sp₃.
In the case of acetylene(HCCH or C₂H₂):
- The carbon atom requires additional electrons to establish four bonds with hydrogen and other carbon atoms in the synthesis of C₂H₂. One 2s₂ pair is consequently transferred to the vacant 2pz orbital. Each carbon has two sp hybrid orbitals after the 2s orbital in each atom combines with one of the 2p orbitals.
- As a result of the atoms' symmetrical alignment in a single plane, C₂H₂ possesses a linear molecular structure. Due to their lower electronegative nature than Hydrogen atoms, all Carbon atoms are situated near the center of the Lewis structure of C₂H₂.
H-C≡C-H
Therefore, it is concluded from the above discussion that the hybridization type of acetylene is 'sp'.
Learn more about hybridization here:
brainly.com/question/14140731
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<h3>Answer:</h3>
Option-B (Halide; oxide) is the correct answer.
<h3>Explanation:</h3>
<em> Halides</em> are those substances which contains negatively charged halide ion i.e. X⁻.
Examples: F⁻ (Fluoride) , Cl⁻ (Chloride) , Br⁻ (Bromide) , I⁻ (Iodide) e.t.c.
<em>Oxides </em>are those substances which atleast containn one Oxygen atom.
Examples: FeO (Iron Oxide), Cr₂O₃ (Chromium Oxide)
<em>Silicates</em> are those anionic substances which contains silicon and oxygen with general formula [SiO. 4−x] n.
Examples: [SiO₄]⁻⁴ (Nasosilicate) , [Si₂O₇]⁻⁶ (Sorosilicates)
<em>Carbonates </em>are those substances which contains carbonate anion i.e. CO₃²⁻.
Examples: Na₂CO₃ (Sodium Carbonate) , MgCO₃ (Magnesium Carbonate)
<h3>Conclusion:</h3>
As in NaCaAlF, F⁻ is present hence, it is an Halide and the presence of O in FeCrO makes it Oxide.
