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Law Incorporation [45]
3 years ago
7

Fe2O3 + CO → Fe + CO2 If 3 moles of Fe2O3 react with 1.5 moles of CO, how many moles of each product are formed? (3 points)

Chemistry
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

A. 1 mole of Fe.

B. 1.5 moles of CO₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Fe₂O₃ + 3CO —> 2Fe + 3CO₂

From the balanced equation above,

1 mole of Fe₂O₃ reacted with 3 moles of CO to produced 2 moles of Fe and 3 moles of CO₂.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of Fe₂O₃ reacted with 3 moles of CO.

Therefore, 3 moles of Fe₂O₃ will react with = 3 × 3 = 9 moles of CO.

From the calculation made above, we can see clearly that it will require a higher amount (i.e 9 moles) of CO than what was given (i.e 1.5 moles) to react completely with 3 moles of Fe₂O₃.

Therefore, CO is the limiting reactant and Fe₂O₃ is the excess reactant.

A. Determination of the number of mole of Fe produced.

NOTE: The limiting reactant is used to obtain the desired result because it will give the maximum yield of the products since all of it is consumed in the reaction.

From the balanced equation above,

3 moles of CO reacted to produced 2 moles of Fe.

Therefore, 1.5 moles of CO will react to produce = (1.5 × 2)/3 = 1 mole of Fe.

Thus, 1 mole of Fe was obtained from the reaction.

B. Determination of the number of mole of CO₂ produced.

From the balanced equation above,

3 moles of CO reacted to produced 3 moles of CO₂.

Therefore, 1.5 moles of CO will also react to produce 1.5 moles of CO₂.

Thus, 1.5 moles of CO₂ were obtained from the reaction.

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3 years ago
How many ml of 2.50 M NaOH solution are required to make a 525 mL of 0.150 M?
larisa [96]

Answer:

31.5 mL of a 2.50M NaOH solution

Explanation:

Molarity (M) is an unit of concentration defined as moles of solute (In this case, NaOH), per liter of solvent. That is:

Molarity = moles solute / Liter solvent

If you want to make 525mL (0.525L) of a 0.150M of NaOH, you need:

0.525L × (0.150mol / L) = <em>0.07875 moles of NaOH</em>

<em />

If you want to obtain these moles from a 2.50M NaOH solution:

0.07875mol NaOH × (1L / 2.50M) = 0.0315L = <em>31.5 mL of a 2.50M NaOH solution</em>

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Why does the light bulbs have to be part of the loop in order for it to be succesful?
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6 0
3 years ago
What amount of carbon dioxide (in moles) is produced from the reaction of 2.24 moles of ethanol with excess oxygen?
algol13

Answer : The amount of carbon dioxide produced is, 197.12 grams.

Explanation : Given,

Moles of ethanol = 2.24 mole

Molar mass of carbon dioxide = 44 g/mole

The balanced chemical reaction will be,

C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O

First we have to calculate the moles carbon dioxide.

From the balanced chemical reaction, we conclude that

As, 1 mole of ethanol react to give 2 moles of carbon dioxide

So, 2.24 mole of ethanol react to give 2\times 2.24=4.48 moles of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2

\text{Mass of }CO_2=4.48mole\times 44g/mole=197.12g

Therefore, the amount of carbon dioxide produced is 197.12 grams.

8 0
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