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Eva8 [605]
3 years ago
7

This is the process that cells reproduce and replace old or damaged cells.

Chemistry
2 answers:
r-ruslan [8.4K]3 years ago
6 0
A. Mitosis

Didnndxbdbdn
Temka [501]3 years ago
3 0
The answer is A. mitosis
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Determine the fraction of an original sample of tritium that remains unchanged after 24.62 years.
patriot [66]

Answer: The answer is 1/4

Explanation:

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3 years ago
Ranging from 0 to 14, a pH value indicates how acidic or basic a solution is. Which of these pH values would be a strong acid? *
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4 0
3 years ago
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What is the density of a substance that weighs 340g and has a volume of 40cm3?
jeka94

Answer:

<h2>8.5 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{340}{40}  =  \frac{17}{2}  \\

We have the final answer as

<h3>8.5 g/cm³</h3>

Hope this helps you

5 0
3 years ago
Estimate ΔH for the reaction using bond dissociation energies from Table 7.1. Give your answer in kcal. C6H12O6 has five C−C bon
Nat2105 [25]

The equation for the photosynthesis reaction in which carbon dioxide and water react to form glucose is . The hear reaction is the difference between the bond dissociation energies in the products and the bond dissociation energies of the reactants

 

The reactant molecules have 12 C = O, 12 H - O bonds while the product molecules have 5 C - C, 7 C – O, 5 H – O, and 6 O = O bonds. The average bond dissociation energies for the bonds involved in the reaction are 191 for C = O, 112 for H – O, 83 C –C, 99 C – H, 86 C – O, 119 O = O.

 

Substitute the average bond dissociation energies in the equation for and calculate as follows

= [12 (C=O) + 12 (H-O)] – [5(C-C) + 7(C-H) + 7 (C-O) + 5(H-O) + 6(O=O)]

= [12x191 kcal/mol + 12x112 kcal//mol] – [5x83 kcal/mol + 7x99 kcal/mol + 7x86 kcal/mol + 5x112 kcal/mol + 6x119 kcal/mol]

= 3636 kcal/mol – 2984 kcal/mol = 652 kcal/mol x 4.184 Kj/1kcal = 2.73x10^3 kJ/mol

 

So, enthalpy change for the reaction is 652 kcal/mol or 2.73x10^3 kJ/mol

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5 0
4 years ago
Why do some elements form double and triple bonds during bonding
jekas [21]

Explanation:

Elements need a total of eight electrons to gain stability and look like a noble gas. So, they sometimes need sharing of two, four or even six electrons to complete their octate. So, they form double and triple covalent bonds. One more  the reason is the  interaction between the p orbitals of the combining atoms. for example  A double bond, as in ethene H2C=CH2, arises from one combination of the s orbitals and one combination of the p_y orbitals.

4 0
3 years ago
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