Rank the following letters in order from greatest to least Potential Energy

while dipping a solid object in a liquid upthrust on the object due to the liquid and the weight of the displaced liquid are sho

a_sh-v [17]

Answer:

If you try to lift up a weight in a swimming pool and then try to lift the same weight on the edge of the pool, it feels much lighter in the water.

This was supposed to have been first explained by the Greek scientist Archimedes. He said that the water gives an upward force or upthrust on any object in it.

You can weigh an object in air and then in water and actually work out the upthrust, it is the difference between the two readings. For this reason the upthrust is often called the loss in weight of the object.

3 0

3 years ago

Find the distance traveled in one back-and-forth swing by the weight of a 12 in. Pendulum that swings through a 75 degree angle.

tia_tia [17]

The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

The period of pendulum can be calculated by

$T = 2\pi \sqrt {\dfrac Lg}$

Where,

$T$ - period

$L$ - length = 12 inches

$g$ - gravitational acceleration = $\bold {9.8\rm \ m/s^2}$

Put the values,

$T = 2\pi \sqrt {\dfrac {12}{9.8}}\\\\T = 2 \times 3.14 \times \sqrt {0.122}\\\\T = 2.191$

Now, the angular displacement of the pendulum can be calculated by,

$\theta = A\times\rm \ cos(\omega T)$

Where,

$A$ - amplitude

$\theta$ - angle = $75^o$

$\omega$ - angular displacement = $2\pi/T$ = 2.866 m

Put the values and calculate for $\omega$ ,

$75 = A\times{\rm \ cos}(2.866\times 2.191)\\\\75 =A \times cos\ 6.26\\\\A =\dfrac {75}{0.99}\\\\A = 75.75 \rm \ inches$

Therefore, the distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

To know more about Amplitude of pendulum,

brainly.com/question/14840171

4 0

3 years ago

A circuit component that is a composed of a semiconductor layer sandwiched between two other semiconductor layers is a(n)?

Alika [10]

Explanation:

It's a transistor. Hope that helps!

8 0

3 years ago

Read 2 more answers

The vector position of an object is given by r what is the torque acting on the object about the origin when a force f = (−12.5i

attashe74 [19]

Let the vector position of the object in the (x-y) plane be
$\vec{r} = x \hat{i} + y \hat{j}$

The applied force is
$\vec{f} = -12.5 \hat{i}
$

By definition, the applied torque is
$\vec{T} = \vec{r} \times \vec{f} = (x\hat{i} + y\hat{j}) \times (-12.5y \hat{i}) = 12.5\hat{k}$

Answer: $12.5y \, \hat{k}$