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lisabon 2012 [21]
3 years ago
11

A ball is thrown horizontally with an initial

Physics
1 answer:
kupik [55]3 years ago
8 0
It’s B I’m not sure it the right one
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What is the MAIN reason water from the oceans turns to water vapor, and then evaporates into the air?
GuDViN [60]

This has a two word answer: sun's heat. The faster moving molecules near the ocean's surface are provided with enough energy from the sun to escape the surface they are near.

 

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1. Calculate the velocity of a 0.8 kg kitten with a forward momentum of 5 kg*m/s.
V125BC [204]

Q.1

Answer . Momentum = mass x velocity

               Momentum/mass = velocity

               5/0.8 = velocity

               6.25 m/s = velocity

Q.2

Answer . F = ma => a = f/m => a = 7/3.2 => a = 2.1875m/s²

3 0
3 years ago
I don’t understand any of it. Please help :(((
klio [65]

Answer:

I know half on number one it is repulsive

Explanation:

5 0
3 years ago
8. A thin slice of silicon that contains many solid-state components is a(n)
Sergio [31]
Question 8
Silicon is a semi-conductor that are mostly used in electronic devices. From the choices give, silicon is applicable in t<span>ransistor, integrated circuit and diode. But the best answer that suits this question is (B) integrated circuit. 

Question 9
Power is the rate of doing work. It is calculated as,

Power = workdone/time taken to do that work.

In electricity, power = current </span>×voltage
From ohm's law, V=IR
Where I⇒current and 
           R⇒ resistance. 

∴Power = I²R
             = 6²×5
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7 0
4 years ago
A charge Q accumulates on the hollow metallic dome, of radius R, of a Van de Graaff generator. A probe measures the electric fie
andre [41]

The electric field changes by a factor 4/9

Explanation:

The electric field at a point outside a hollow charged sphere is identical to that produced by a single point charge Q, therefore its strength is given by

E=k\frac{Q}{r^2}

where

k is the Coulomb constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

In this problem, we have a charge Q accumulated on the dome of the generator of radius R. The electric field strength at a distance of 2R from the sphere centre is

E=\frac{kQ}{(2R)^2}=\frac{1}{2}\frac{kQ}{R^2}

Then, the probe is moved to a new distance of

r = 3R

From the centre of the sphere: therefore, the new electric field will be

E'=\frac{kQ}{(3R)^2}=\frac{1}{9}\frac{kQ}{R^2}

So, the electric field has changed by a factor

\frac{E'}{E}=\frac{1/9}{1/4}=\frac{4}{9}

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

7 0
3 years ago
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