A ball is thrown horizontally with an initial
1 answer:
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The electric field changes by a factor 4/9
Explanation:
The electric field at a point outside a hollow charged sphere is identical to that produced by a single point charge Q, therefore its strength is given by
where
k is the Coulomb constant
Q is the charge on the sphere
r is the distance from the centre of the sphere
In this problem, we have a charge Q accumulated on the dome of the generator of radius R. The electric field strength at a distance of 2R from the sphere centre is
Then, the probe is moved to a new distance of
r = 3R
From the centre of the sphere: therefore, the new electric field will be
So, the electric field has changed by a factor
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