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3 years ago

9

A baseball thrown from the outfield to home plate does not have which of the following types of energy while it's in the air? A.

Gravitational potential energy B. Mechanical energy C. Kinetic energy D. Radiant energy

1 answer:

posledela3 years ago

7 0

The ball does not have D. Radiant energy.

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The human body contains many examples of a lever, true or false?

sertanlavr [38]

well yes i believe the arms and legs count as levers

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4 years ago

How do tunicates and lancelets differ from other chordates?

faltersainse [42]

<span>During their embryonic stage they have a flexible cord that supports their bodies which disappears in the adult stage. Some of these develop bones surrounding the cord in the adult stage rather than have it disappear.</span>

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3 years ago

A positron with kinetic energy 2.30 keV is projected into a uniform magnetic field of magnitude 0.0980 T, with its velocity vect

Mama L [17]

Answer:

a)0.364 ns

b)1.43 x 10^-3

c)163.21 x 10^-5 m

Explanation:

mass of the positron is m=9.1 x 10^-31 kg

charge is q=1.6 x 10^-19 C

strength of the magnetic field is B=0.0980 T

kinetic energy is K=2.30 keV=2.30 x 10^3 x 1.6 x 10^-19 J

0.5mv^2=6.68 x 10^-16 J

0.5 x 9.1 x 10^-31 x v^2 =3.68 x 10^-16

v=2.84 x 10^7 m/s

a)the period is T=2πm/qB

=2π(9.1 x 10^-31 )/1.6 x 10^-19x 0.0980

=0.364 ns

b) pitch is p=vcosθ(2πm/qB)

=2.84 x 10^7x cos82(0.364 x 10^-9)

=1.43 x 10^-3

c) radius is r=mvsinθ/qB

=(9.1 x 10^-31 )2.84 x 10^7x sin82/1.6 x 10^-19x 0.098

=163.21 x 10^-5 m

3 0

3 years ago

Read 2 more answers

What does the chemical formula CaCl2 show about the compound it represents?

Assoli18 [71]

C6H12O2 C6H12O2 C6H12O2 C6H12O2 <span>C6H12O2</span>

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3 years ago

A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one

alekssr [168]

Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R= $13\Omega$

Resistance is directly proportional to length.

If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

Total resistance of copper wire=Sum of resistance of two piece of wires

$r+7r=13$

$8r=13$

$r=\frac{13}{8}$ ohm

Resistance of long piece of wire= $7\times\frac{13}{8}=\frac{91}{8}\Omega$

Resistance of short piece of wire = $\frac{13}{8}\Omega$

Resistivity of wire and cross section area of wire remains same .

Let L be the total length of wire and L' be the length of short piece of wire.

We know that

$R=\frac{\rho L}{A}$ = $\frac{\rho}{A}L=KL$

$\frac{R}{L}=K$

Where K= $\frac{\rho}{A}$ =Constant

Using the formula

$\frac{13}{L}=\frac{\frac{13}{8}}{L'}$

$\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}$

$L'=\frac{L}{8}$

Length of short piece of wire=L'= $\frac{L}{8}$

Length of long piece of wire= $L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L$

% of length of short piece of wire= $\frac{\frac{L}{8}}{L}\times 100=12.5%$ %

The resistance of the short piece= $\frac{13}{8}\Omega$

The resistance of the long piece= $\frac{91}{8}\Omega$

8 0

4 years ago