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likoan [24]
3 years ago
9

An object is dropped into a beaker containing liquid the object drops to the bottom of the beaker therefore

Physics
1 answer:
Wittaler [7]3 years ago
7 0
The objects density is greater than one
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Acceleration is measured in_________<br><br><br> m<br><br><br> g<br><br><br> m/s<br><br><br> m/s2
Nana76 [90]
Acceleration is measured in m/s².

Answer: m/s²
4 0
4 years ago
The diagram below shows the muzzle of a cannon located 50. meters above the ground. When the cannon is fired, a ball leaves the
Nastasia [14]

Answer:positioning the cannon higher above the ground

Explanation:

❤️

5 0
3 years ago
Consider a simple pendulum that consists of a massless 2.00-meter length of rope attached to a 5.00-kg mass at one end. What is
Papessa [141]

Answer:

2.8 seconds

Explanation: Given that a simple pendulum that consists of a massless 2.00-meter length of rope attached to a 5.00-kg mass at one end. What is the period of oscillation for this simple pendulum

The parameters given are :

Length = 2 m

Mass = 5kg

Using the formula below

T = 2 pi × sqrt ( L / g )

Substitute all the parameters into the formula.

T = 2 × 3.143 × sqrt ( 2 / 9.8 )

T = 2 × 3.143 × 0.4517

T = 2.838 s

Therefore, the period of oscillation for this simple pendulum is 2.8 s approximately.

8 0
3 years ago
The kinetic energy of a 44 kg-cheetah running at 31 m/s is
iren2701 [21]
The answer is 21142 Joules hope this helped cause im sorry if this didnt
7 0
3 years ago
A 1500 kg car, initially traveling at 22.0 m/s, hits its brakes and skids to a stop. Determine the work done by friction.
Sedbober [7]

Answer:

<em>The work done by the car is 363 kJ</em>

Explanation:

Work : Work is said to be done when a Force moves an object through a certain distance. Work and Energy are interchangeable because they have the same unit. The unit of work is Joules (J).

Mathematically work done can be expressed as,

E = W = 1/2mv²

W =  1/2mv²................................ Equation 1

Where E = Energy, W = work done, m = mass of the car, v = velocity of the car

<em>Given: m=1500 kg, v=22 m/s</em>

<em>Substituting these values into equation 1</em>

<em>W = 1/2(1500)(22)²</em>

<em>W = 750 × 484</em>

<em>W = 363000 J</em>

<em>W = 363 kJ</em>

<em>Thus the work done by the car is 363 kJ</em>

8 0
3 years ago
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