Question

Intensity: Radiation of a single frequency reaches the upper atmosphere of the earth with an intensity of 1350 W/m2. What is the maximum value of the electric field associated with this radiation? (c = 3.00 × 108 m/s, μ0 = 4π × 10-7 T ∙ m/A, ε0 = 8.85 × 10-12 C2/N ∙ m2)

Answer 1

Answer:

The right answer is "1010 V/m".

Explanation:

The given values are:

Intensity,

$I=1350 \ W/m^2$

$c = 3.00\times 108 \ m/s$

$\mu_0= 4\pi\times 10^{-7} \ T.m/A$

Now,

The electric field's maximum value will be:

=  $\sqrt{2\times u\times c\times I}$

On substituting the values in the above formula, we get

=  $\sqrt{2\times 4\times \pi\times 10^{-7}\times 3\times 10^8\times 1350}$

=  $\sqrt{32400\times 3.14\times 10^{-7}\times 10^8}$

=  $1010 \ V/m$