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AURORKA [14]
3 years ago
8

Intensity: Radiation of a single frequency reaches the upper atmosphere of the earth with an intensity of 1350 W/m2. What is the

maximum value of the electric field associated with this radiation? (c = 3.00 × 108 m/s, μ0 = 4π × 10-7 T ∙ m/A, ε0 = 8.85 × 10-12 C2/N ∙ m2)
Physics
1 answer:
sesenic [268]3 years ago
3 0

Answer:

The right answer is "1010 V/m".

Explanation:

The given values are:

Intensity,

I=1350 \ W/m^2

c = 3.00\times 108 \ m/s

\mu_0= 4\pi\times 10^{-7} \ T.m/A

Now,

The electric field's maximum value will be:

=  \sqrt{2\times u\times c\times I}

On substituting the values in the above formula, we get

=  \sqrt{2\times 4\times \pi\times 10^{-7}\times 3\times 10^8\times 1350}

=  \sqrt{32400\times 3.14\times 10^{-7}\times 10^8}

=  1010 \ V/m

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Which of the following is a Nobel gas?<br> Ba2+<br> OA<br> OB. Ci<br> Kr<br> Ос.<br> Ca<br> D.
stepan [7]

Answer:

Kr

Explanation:

the element that is in group 18 is noble gasses. the elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

5 0
3 years ago
Determine whether the following statements are true or false and give an explanation or counter example. a. If the acceleration
tester [92]

Answer:

If the acceleration of an object remains​ constant, then its velocity is constant. False

If the acceleration of an object moving along a line is always​ 0, then its velocity is constant. True

It is impossible for the instantaneous velocity at all times aless than or equalstless than or equalsb to equal the average velocity over the interval aless than or equalstless than or equalsb. True

A moving object can have negative acceleration and increasing speed. False

Explanation:

First of all, before we can talk of acceleration, then there must be a change in velocity. If the velocity of a body is constant, then there will not be any acceleration at all.

If the acceleration is zero, then there is no change in velocity, the velocity is constant.

The instantaneous velocity is always changing all through the motion hence it cannot be determined at all times to equal the average velocity.

If the acceleration is negative, it simply means that the velocity is decreasing with time. Hence there can't be a negative acceleration and increasing velocity.

5 0
3 years ago
Please annswer will the correct letter I WILL GIVE BRAINLIEST MUST ANSWER BOTH :)
erica [24]
C  and A the first one is a bit weird but thats what i got and you cant even see it that good
3 0
3 years ago
Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are 0.50 L, 2.
aleksklad [387]

Answer:

13.524 N

Explanation:

Volume and densities are given as:

ρ1 = 2.6 g/cm³ => 2600 kg/m³ ; V1 = 0.50 L => 0.5 x 10^-3 m³

ρ2 = 1.0 g/cm³ => 1000 kg/m³ ; V2= 0.25 L => 0.25 x 10^-3 m³

ρ3 = 0.7 g/cm³ => 700 kg/m³ ; V3 = 0.4 L => 0.4 x 10^-3 m³

Next is to calculate force exerted on the bottom of the container due to these liquids:

F= ρ1V1g + ρ2 V2 g+ ρ 3 V3g

where ,

ρ= density

V= volume

g= 9.8m/s²

F= g( 2600 x 0.5 x 10^-3 + 1000 x 0.25 x 10^-3 + 700 x 0.4 x 10^-3)

F= 9.8 (1.38)

F=  13.524 N

Therefore,  the force on the bottom of the container due to these liquids is 13.524 N

6 0
4 years ago
A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
kherson [118]

Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

Explanation:

Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.

The time taken by the object to hit the ground is calculated by:

\displaystyle t=\sqrt{\frac{2h}{g}}

The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

\displaystyle d=v.t

The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.

a,

The time taken by the rock to reach the ground is:

\displaystyle t=\sqrt{\frac{2*20}{9.8}}

\displaystyle t=\sqrt{4.0816}

t = 2.02 s

The rock takes 2.02 seconds to hit the ground

b.

The range is calculated now:

\displaystyle d=10\cdot 2.02

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

5 0
3 years ago
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