The rate of energy radiated by the man is 3.86 x J/s. .
The amount of energy radiated by an object majorly depends on the area of its surface and its temperature. The is well explained in the Stefan-Boltzmann's law which states that:
Q(t) = Aeσ
where: Q is the quantity of heat radiated, A is the surface area of the object, e is the emmisivity of the object, σ is the Stefan-Boltzmann constant and T is the temperature of the object.
To determine the rate of energy radiated by the man in the given question;
= Aeσ
But A = 1.7 m², e = 0.4 and σ = 5.67 x J/s.
So that;
= 1.7 * 0.4 * 5.67 x
= 3.8556 x
= 3.86 x J/s.
Thus, the rate of energy radiated by the man is 3.86 x J/s. .
Learn more on energy radiation of objects by visiting: brainly.com/question/12550129
Answer:
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Explanation:
Answer:
16
Explanation:
The formula for the force of attraction between two charges is , where k is a constant, is the first charge, and is the second charge. As you can see, if the radius or distance increases by 2, the force decreases by 4 because it grows exponentially. However, if the charge of one of the particles increases by 2, the force between the two also increases by 2. Therefore, the new force will be 8*2=16. Hope this helps!
Answer:
519.62 m/s
Explanation:
Applying,
v = √(T/m').............. Equation 1
Where v = velocity of the wave, T = Tension on the string, m' = mass per unit length of the string
From the question,
Given: T = 1350 N, m' = 0.005 kg/m
Substitute these values into equation 1
v = √(1350/0.005)
v = √(270000)
v = 519.62 m/s