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Angelina_Jolie [31]
3 years ago
12

Calculate the pressure in atm of .68 mol of H at 298K and occupying 4.5 L

Chemistry
1 answer:
inessss [21]3 years ago
5 0

Answer:

3.7 atm

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Moles

<u>Gas Laws</u>

Ideal Gas Law: PV = nRT

  • <em>P</em> is pressure
  • <em>V</em> is volume
  • <em>n</em> is number of moles
  • <em>R</em> is gas constant
  • <em>T</em> is temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>n</em> = 0.68 mol H

[Given] <em>T</em> = 298 K

[Given] <em>V</em> = 4.5 L

[Given] <em>R</em> = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] <em>P</em>

<em />

<u>Step 2: Find Pressure</u>

  1. Substitute in variables [Ideal Gas Law]:                                                          P(4.5 L) = (0.68 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)(298 K)
  2. Multiply [Cancel out units]:                                                                               P(4.5 L) = (0.055828 L · atm · K⁻¹)(298 K)
  3. Multiply [Cancel out units]:                                                                               P(4.5 L) = 16.6367 L · atm
  4. Isolate <em>P</em> [Cancel out units]:                                                                             P = 3.69705 atm

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

3.69705 atm ≈ 3.7 atm

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