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Angelina_Jolie [31]
3 years ago
12

Calculate the pressure in atm of .68 mol of H at 298K and occupying 4.5 L

Chemistry
1 answer:
inessss [21]3 years ago
5 0

Answer:

3.7 atm

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Moles

<u>Gas Laws</u>

Ideal Gas Law: PV = nRT

  • <em>P</em> is pressure
  • <em>V</em> is volume
  • <em>n</em> is number of moles
  • <em>R</em> is gas constant
  • <em>T</em> is temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>n</em> = 0.68 mol H

[Given] <em>T</em> = 298 K

[Given] <em>V</em> = 4.5 L

[Given] <em>R</em> = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] <em>P</em>

<em />

<u>Step 2: Find Pressure</u>

  1. Substitute in variables [Ideal Gas Law]:                                                          P(4.5 L) = (0.68 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)(298 K)
  2. Multiply [Cancel out units]:                                                                               P(4.5 L) = (0.055828 L · atm · K⁻¹)(298 K)
  3. Multiply [Cancel out units]:                                                                               P(4.5 L) = 16.6367 L · atm
  4. Isolate <em>P</em> [Cancel out units]:                                                                             P = 3.69705 atm

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

3.69705 atm ≈ 3.7 atm

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Explanation:

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3 years ago
List three properties if the elements that are useful in sorting the elements.
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A sample of helium has a volume of 50.00 L at STP. How many helium atoms are in the sample? Show work
Setler79 [48]

Answer:

Explanation:

molar volume at STP=22.4 L

given volume=50.0 L

number of moles=given volume/molar volume

number of moles=50.0/22.4

number of moles=2.2

1 mole of helium =6.023*10^23 atoms

2.2 moles of helium =6.023*10^23*2.2=1.3*10^24

therefore 50.0 L of helium contain 1.33*10^24 atoms

4 0
3 years ago
A gas occupies 3.5L at 2.5 kPa pressure. What is the volume at 100 mmHg at the same temperature? Be sure to
nataly862011 [7]

Answer:

V₂ = 0.656 L

Explanation:

Given data:

Initial volume = 3.5 L

Initial pressure = 2.5 KPa

Final volume = ?

Final pressure = 100 mmHg (100/7.501=13.33 KPa)

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

2.5 KPa × 3.5 L = 13.33 KPa × V₂

V₂ = 8.75 KPa. L/13.33 KPa

V₂ = 0.656 L

7 0
3 years ago
How many hydrogen atoms are in 35.0 grams of hydrogen gas? How many hydrogen atoms are in 35.0 grams of hydrogen gas? 4.25 × 102
Ede4ka [16]

Answer: 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{35.0g}{2g/mol}=17.5moles

1 mole of hydrogen (H_2) = 2\times 6.023\times 10^{23}=12.05\times 10^{23} atoms

17.5 mole of hydrogen (H_2) = \frac{12.05\times 10^{23}}{1}\times 17.5=2.12\times 10^{25} atoms

There are 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

8 0
3 years ago
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