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e-lub [12.9K]
3 years ago
11

An object moves from point A to B to C to D and finally to A

Physics
1 answer:
Nataly [62]3 years ago
5 0

here's the solution,

The <em>radius</em> of the circle =<u> 3 km</u>

distance covered = <em>circumference</em> of the circle,

So, Circumference :

=》

2\pi r

=》

2 \times 3.14 \times 3

=》

18.84

(a). Distance covered by moving object is 18.84 km

(b). 0 km

now, Displacement of the object is 0 km, because displacement is the shortest distance from stating point to the destination, but the object returns back to the starting point, hence magnitude of displacement is 0.

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A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for
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Answer:

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Explanation:

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N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

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m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f} (2)

Where:

v_{o}, v_{f} - Initial and final speeds of the block, measured in meters per second.

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\Delta t - Impact time, measured in seconds.

Now we clear the final speed in (2):

v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}

If we know that v_{o} = 0\,\frac{m}{s}, m = 14\,kg, \Sigma F = 98\,N and \Delta t = 1.40\,s, then final speed of the ice block is:

v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}

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