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3 years ago

An object moves from point A to B to C to D and finally to A

Physics

1 answer:

Nataly [62]3 years ago

5 0

here's the solution,

The radius of the circle = 3 km

distance covered = circumference of the circle,

So, Circumference :

=》

$2\pi r$

=》

$2 \times 3.14 \times 3$

=》

$18.84$

(a). Distance covered by moving object is 18.84 km

(b). 0 km

now, Displacement of the object is 0 km, because displacement is the shortest distance from stating point to the destination, but the object returns back to the starting point, hence magnitude of displacement is 0.

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A 6 kg mass collides with a body at rest .After collision they travel together with a velocity equal

Mars2501 [29]

Answer:

12 kg

Explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

After the collision, they have the same velocity, so v₁ = v₂ = v:

m₁ u₁ + m₂ u₂ = m₁ v + m₂ v

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

We know that m₁ = 6 kg, u₂ = 0 m/s, and v = u₁ / 3.

(6 kg) u₁ + m₂ (0 m/s) = (6 kg + m₂) (u₁ / 3)

(6 kg) u₁ = (6 kg + m₂) (u₁ / 3)

6 kg = (6 kg + m₂) (1/3)

18 kg = 6 kg + m₂

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3 0

4 years ago

metal cap is the negative terminal of an electric cell true or false please send me the answer please

USPshnik [31]

Answer:

false. it's positive terminal of an electric cell

7 0

3 years ago

A body is thrown up with a velocity of 78.4 m per second.How high will it rise and how much time it will take to return to its p

a_sh-v [17]

Answer:

The maximum height reached by the body is 313.6 m

The time to return to its point of projection is 8 s.

Explanation:

Given;

initial velocity of the body, u = 78.4 m/s

at maximum height (h) the final velocity of the body (v) = 0

The following equation is applied to determine the maximum height reached by the body;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (78.4²) / (2 x 9.8)

h = 313.6 m

The time to return to its point of projection is calculated as follows;

at maximum height, the final velocity becomes the initial velocity = 0

h = v + ¹/₂gt²

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

t² = 2h/g

$t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 313.6}{9.8} }\\\\t = 8 \ s$

4 0

3 years ago

Consider a loop of wire whose plane is horizontal and that carries a current in the clockwise direction when viewed from above.

Mars2501 [29]

Answer:

Downwards into the plane

Explanation:

Solution:-

- This is a conceptual application of hand rule. We will place our palm fingers open vertical to a plane surface. Then curl our fingers in and naturally point the thumb.

- The direction of curl of fingers denotes the direction of of current flow in the coil. Which in our case is "clockwise direction". We will orient/invert our right hand palm in such a way that we curl our fingers in clockwise fashion. Then stick the thumb out to give us the direction of magnetic field or North pole end. In our case the the thumb points downwards into the plane denoting that the magnetic field within the loop is also acting downwards into the plane.

- The bar magnet would be placed in such a way that North pole is pointing downward into the plane in the direction of magnetic field and end up at south pole pointing up out of the plane.

7 0

3 years ago

A pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. What is the acceleration experie

sweet-ann [11.9K]

Answer:

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