<span>v=u+at</span>
<span>
0=5.0283−9.8×t</span><span>
t=0.5130sec</span><span>
Total time = 2t = 1.0261 sec</span>
Answer:
You can get w =Fxd 20Nx5m w=100N energy= w÷t 100N÷4s E=25J 3 you can apply 3J in one second
Answer:
(a) v1 = 21.6 m/s
(b) t = 51.25 s
Explanation:
Use kinematics equation
v1 = v0 + at
Given
v0 = 0 = initial velocity
a = 0.8 m/s^2 = acceleration
(a) t = 27 seconds
v1 = v0 + at = 0 + 0.8*27 = 21.6 m/s
(b) v1 = 41 m/s
v1 = v0 + at
solve for t
t = (v1-v0)/a = (41-0)/0.8 = 51.25 s
Answer:
An elements atomic number will never change, that is because the atomic number is its "identity."
We can solve the problem by using the law of conservation of energy.
Initially, the rock has only gravitational potential energy, which is given by

where mg is the weigth of the rock (2200 N), while h is the height at which the rock has been released (h=15 m). If we calculate it, we get

Just before hitting the ground, the rock height is zero, so its potential energy is now zero. So the total mechanical energy of the rock now is just kinetic energy:

however, the mechanical energy of the rock must be conserved, so

and so we have that the kinetic energy of the rock just before hitting the ground is equal to its initial potential energy: