Answer:
By altering the quantum interactions of the electrons in the atoms of a metal's atoms, scientists from the University of Leeds have generated magnetism in metals that aren’t normally magnetic.
Explanation:
Answer:children burn calories to being a student
Explanation:That mean when a children getting ready to go to high school
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Explanation:
The wave property which is independent of all other properties is THE VELOCITY OF A WAVE.
The velocity of a wave is defined as the distance moved by a cyclic motion per unit time. The velocity of a wave is determined by the properties of the medium through which it moves; it does not not depend on the properties of the wave itself.
Answer:
Let's investigate the case where the cable breaks.
Conservation of angular momentum can be used to find the speed.

The projectile embeds itself to the ball, so they can be treated as a combined object. <u>The moment of inertia of the combined object is equal to the sum of the moment of inertia of both objects. </u>

where r is the length of the cable.
<u>After the collision, the ball and the projectile makes a circular motion because of the cable.</u> So, the force (tension) in circular motion is

The relation between linear velocity and the angular velocity is

So,

As can be seen, the maximum velocity for the projectile without breaking the cable is
, where r is the length of the cable.