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Mama L [17]
2 years ago
6

7 H2SO4 what is the coefficient? what are the subscript numbers?

Chemistry
1 answer:
baherus [9]2 years ago
3 0

Answer:

Coefficient: number balancing sulfuric acid in a chemical reaction.

Subscripts: number of atoms of each element forming the compound.

Explanation:

Hello!

In this case, since sulfuric acid is a molecule containing hydrogen, sulfur and oxygen in the following way:

- Two hydrogen atoms.

- One sulfur atom.

- Four oxygen atoms.

We can notice the 2 at H represents those two hydrogen atoms, the subscriptless S represent that 1 sulfur atom and the 4 at O represents those four oxygen atoms.

Moreover, since the molecules is given as 7 H2SO4 ; from stoichiometry, we infer that every number preceding the molecule stands for a coefficient which is used to balance a undergoing chemical reaction reaction.

Best regards!

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Calculate how many grams of the first reactant are necessary to completely react with 17.3 g of the second reactant. the reactio
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Taking into account the reaction stoichiometry, 16.611 grams of Na₂CO₃ are necessary to completely react with 17.3 g of CuCl₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Na₂CO₃ + CuCl₂  → CuCO₃ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • CuCl₂: 1 mole
  • CuCO₃: 1 mole
  • NaCl: 2 moles

The molar mass of the compounds is:

  • Na₂CO₃: 129 g/mole
  • CuCl₂: 134.45 g/mole
  • CuCO₃: 123.55 g/mole
  • NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Na₂CO₃: 1 mole ×129 g/mole= 129 grams
  • CuCl₂: 1 mole ×134.45 g/mole= 134.45 grams
  • CuCO₃: 1 mole ×123.55 g/mole= 123.55 grams
  • NaCl: 2 mole ×58.45 g/mole=116.9 grams

<h3>Mass of CuCl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 134.35 grams of CuCl₂ react with 129 grams of Na₂CO₃, 17.3 grams of CuCl₂ react with how much mass of Na₂CO₃?

mass of Na₂CO₃= (17.3 grams of CuCl₂× 129 grams of Na₂CO₃)÷ 134.35 grams of CuCl₂

<u><em>mass of Na₂CO₃= 16.611 grams</em></u>

Finally, 16.611 grams of Na₂CO₃ is required.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

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