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Mama L [17]
2 years ago
6

7 H2SO4 what is the coefficient? what are the subscript numbers?

Chemistry
1 answer:
baherus [9]2 years ago
3 0

Answer:

Coefficient: number balancing sulfuric acid in a chemical reaction.

Subscripts: number of atoms of each element forming the compound.

Explanation:

Hello!

In this case, since sulfuric acid is a molecule containing hydrogen, sulfur and oxygen in the following way:

- Two hydrogen atoms.

- One sulfur atom.

- Four oxygen atoms.

We can notice the 2 at H represents those two hydrogen atoms, the subscriptless S represent that 1 sulfur atom and the 4 at O represents those four oxygen atoms.

Moreover, since the molecules is given as 7 H2SO4 ; from stoichiometry, we infer that every number preceding the molecule stands for a coefficient which is used to balance a undergoing chemical reaction reaction.

Best regards!

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Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

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Explanation :

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For the given chemical equation:

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Rate law expression for the reaction:

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b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

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