Answer:
149.79
Explanation:
Formula
Joules = m * c * delta (t)
Givens
J = 28242
m = ?
c = 4.19
Δt = 63 - 18 = 45
Solution
28242 = m * 4.19 * 45
28242 = m * 188.55
m = 28242 / 188.55
m = 149.79
Answer:
79.04 L
Explanation:
We are given;
Initial Volume; V1 = 6.24L
Initial Pressure; P1 = 760 mm Hg
Final pressure; P2 = 60.0mm Hg
To solve for final volume, we will use Boyles law;
P1•V1 = P2•V2
Let's make V2 which is the final volume the subject;
V2 = (P1•V1)/P2
V2 = (760 × 6.24)/60
V2 = 79.04 L
Answer:
0.159 \%
Explanation:
The acid will dissociate according to the reaction shown below:-
![RCOOH + H_2O\rightleftharpoons RCOO^- + H_3O^+](https://tex.z-dn.net/?f=RCOOH%20%2B%20H_2O%5Crightleftharpoons%20RCOO%5E-%20%2B%20H_3O%5E%2B)
Given that, pH=3.8
The concentration of can be determined from the expression fo pH as:-
pH = - log ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
3.8 = - log ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
= ![1.59\times 10^{-4}\ M](https://tex.z-dn.net/?f=1.59%5Ctimes%2010%5E%7B-4%7D%5C%20M)
The initial concentration of RCOOH was 0.10 M, then the percent dissociation was- calculated as shown below:-
![\% \ dissociation=\frac{1.59\times 10^{-4}}{0.10}\times 100=0.159\ \%](https://tex.z-dn.net/?f=%5C%25%20%5C%20dissociation%3D%5Cfrac%7B1.59%5Ctimes%2010%5E%7B-4%7D%7D%7B0.10%7D%5Ctimes%20100%3D0.159%5C%20%5C%25)
Explanation:
b and c are true statements