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Lina20 [59]
3 years ago
8

Question 5 Value of the impulse function at t - O is defined as​

Engineering
1 answer:
Lady_Fox [76]3 years ago
4 0
The problem of the Graduation date about the cover was that we had a new name on the back of the earth lol but
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Technician A says that applying too much braking force can cause tires to lose traction. Technician B says that ABS systems have
Deffense [45]

Answer:

technically both are correct but tech b is more correct because generally the older the vehicle the worse abs is newer vehicles have abs that no matter how hard you push on the brake peddle the wheels shouldnt lock up

Explanation:

7 0
4 years ago
If you are a government authority what extend will you modify the existing policy
mr_godi [17]

Answer:

kk

Explanation:

dkdndidodd ndidkjeeiwonejeeidmdnddkdidfmndd

4 0
4 years ago
You are preparing to work with Chemical A. You open the appropriate storage cabinet, and notice Chemical B, as well as Chemical
PtichkaEL [24]

The correct answer is; Stability and reactivity.

Further Explanation:

The stability and reactivity section of the SDS sheets is where to check for the possibility of hazardous reactions for the chemicals. This also lists the chemical stability of each chemical that people may be using. This can be found in section 10 of the OSHA Quick Card.

The SDS sheets has 16 sections for employees to use. Since 2015, the sections can be found in uniform format for easier and faster ways to find the section needed. The 16 sections for the SDS sheets are:

  1. Identification
  2. Hazard(s) identification
  3. Composition/information on ingredients
  4. First-aid measures
  5. First-aid measures
  6. First-aid measures
  7. Handling and storage
  8. Exposure controls/personal protection
  9. Physical and chemical properties
  10. Stability and reactivity
  11. Toxicological information
  12. Ecological information
  13. Disposal considerations
  14. Transport information
  15. Regulatory information
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Learn more about SDS sheets at brainly.com/question/9753408

#LearnwithBrainly

5 0
3 years ago
1 2 3 4 5 6 7 8 9 10
Nataly_w [17]
Outdoor advertising
8 0
4 years ago
Assume we have already defined a variable of type String called password with the following line of code: password' can have any
omeli [17]

Answer:

The Java code is given below with appropriate comments for better understanding

Explanation:

import java.util.Scanner;

public class ValidatePassword {

  public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

          System.out.print("Enter a password: ");

          String password = input.nextLine();

          int count = chkPswd(password);

          if (count >= 3)

              System.out.println("Secure");

          else

              System.out.println("Not Secure");

  }

  public static int chkPswd(String pwd) {

      int count = 0;

      if (checkForSpecial(pwd))

          count++;

      if (checkForUpperCasae(pwd))

          count++;

      if (checkForLowerCasae(pwd))

          count++;

      if (checkForDigit(pwd))

          count++;

      return count;

  }

  // checks if password has 8 characters

  public static boolean checkCharCount(String pwd) {

      return pwd.length() >= 7;

  }

  // checks if password has checkForUpperCasae

  public static boolean checkForUpperCasae(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isLetter(pwd.charAt(i)) && Character.isUpperCase(pwd.charAt(i)))

              return true;

      return false;

  }

  public static boolean checkForLowerCasae(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isLetter(pwd.charAt(i)) && Character.isLowerCase(pwd.charAt(i)))

              return true;

      return false;

  }

  // checks if password contains digit

  public static boolean checkForDigit(String pwd) {

      for (int i = 0; i < pwd.length(); i++)

          if (Character.isDigit(pwd.charAt(i)))

              return true;

      return false;

  }

  // checks if password has special char

  public static boolean checkForSpecial(String pwd) {

      String spl = "[email protected]#$%^&*(";

      for (int i = 0; i < pwd.length(); i++)

          if (spl.contains(pwd.charAt(i) + ""))

              return true;

      return false;

  }

}

5 0
3 years ago
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