The EMF of the battery includes the force to to drive across its internal resistance. the total resistance:
R = internal resistance r + resistance connected rv
R = r + rv
Now find the current:
V 1= IR
I = R / V1
find the voltage at the battery terminal (which is net of internal resistance) using
V 2= IR
So the voltage at the terminal is:
V = V2 - V1
This is the potential difference vmeter measured by the voltmeter.
Acceleration = vf-vi /t
10-22/3=2.6m/s^2
Answer:
c Like/same signs
Explanation:
A repelling force occurs between two or more charged objects with the charges are of like or same sign.
- According to Coulombs law, like charges repel on another, unlike charges attracts on another.
- If a positive charge comes into the vicinity of another positive charge, there will be repulsion.
- When oppositely charge species are brought near each other, there is an attraction.
Therefore, repulsion occurs when like charges are brought close to each other.
Answer:
The strength of the magnetic field is 
.
Explanation:
Given that,
Length of the rod, L = 1.01 m
Speed with which the rod is moving, v = 3.47 m/s
We need to find the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.265 mV across the rod. When the rod is moving with some speed, an emf gets induced and it is given by :
B is magnetic field
So, the strength of the magnetic field is .
