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Deffense [45]
3 years ago
8

Define project torque

Physics
1 answer:
pogonyaev3 years ago
8 0

Answer:

ExplanProject Torque was the free North American version of Level-R. It is a multiplayer online racing game (MMORG) with partially chargeable content, or micro-transactions. It features gameplay elements such as tuning and customization. The game is titled as Level R in Europe with a slightly different game interface and menus. Europe, US, Russia, Indonesia, Thailand, China, and Japan versions, are developed by Invictus Games and are subject to Invictus copyrightation:

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Can I improve the design of my simple machine? How?
blsea [12.9K]

Answer:

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Explanation:

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5 0
3 years ago
How much metabolic energy is required for a 68kg person to run at a speed of 15km/hr for 15min ?
irga5000 [103]
<span>What I have here is exactly the same problem, however, with the time changed to 19 mins:

metabolic energy = metabolic power*time = 1.150*19*60 = 1.311 kJ..corresponding to 1.311/4.186 = 313,2 Cal or kcal 

If we reasonably assume a metabolic eff.cy of 20%, it means we need to assume food for 1500 Cal approx.

Just plug the value t=15min to the equation and you will surely get the correct answer.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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8 0
3 years ago
person b does twice the work of person a, and in one-half of the time . how does the power output of person b compare to person
Gwar [14]

Answer:

Person B has four times the power output of person A.

6 0
3 years ago
a 1600 kg car on flat ground is moving 6.25 m/s. its engine creates 1150 N forward force as the car moves 45.8 m. what is it fin
Sveta_85 [38]

Answer:

83,900 J

Explanation:

First, find the acceleration:

F = ma

1150 N = (1600 kg) a

a = 0.719 m/s²

Now find the final velocity.

Given:

Δx = 45.8 m

v₀ = 6.25 m/s

a = 0.719 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (6.25 m/s)² + 2 (0.719 m/s²) (45.8 m)

v = 10.2 m/s

Now find the final KE:

KE = ½ mv²

KE = ½ (1600 kg) (10.2 m/s)²

KE = 83,920 J

Rounded to three significant figures, the final kinetic energy is 83,900 J.

6 0
4 years ago
Find the equilibrant of two 10.0-N forces acting upon a body when the angle between the forces is 90° Solve graphically using a
bazaltina [42]

The equilibrant force of the two given forces is 14.14 N.

<h3 /><h3 /><h3>What is equilibrant force?</h3>
  • This is a single force that balances other given forces.

The given parameters:

  • First force, F₁ = 10 N
  • Second force, F₂ = 10 N
  • Angle between the forces, θ = 90⁰

The equilibrant force of the two given forces is calculated as follows;

F = \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{(10)^2 + (10)^2} \\\\F = 14.14 \ N

Thus, the equilibrant force of the two given forces is 14.14 N.

Learn more about equilibrant force here: brainly.com/question/8045102

5 0
2 years ago
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