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grin007 [14]
3 years ago
14

a = v1-v2/t equation is the equation for calculating the acceleration of an object. Write out the relationship shown in the equa

tion, using words.
Physics
2 answers:
likoan [24]3 years ago
8 0

Answer:

v1-v2 is the change in velocity and t is the time

Explanation:

Acceleration is defined as the change in velocity of a body with respect to time.

According to the equation of acceleration given in question;

a = v1-v2/t

The variables in the equation are defined as thus;

a is the acceleration

v1-v2 is the change in velocity of the body where;

v1 will be the final velocity of the body

v2 is the initial velocity of the body

t is the time taken by the body to accelerate.

Lena [83]3 years ago
5 0
My answer is. Acceleration is the difference between velocities at two times divided by the difference in the times.
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3 years ago
Please help! This is due tomorrow and I absolutely need help.
zysi [14]

Answer:

Correct answer:  11. Total distance d = 200m ; 12. Vav = 3.63m/s ;

13. Total displacement Dt = 0m ; 14. V₂(10s-15s) = 0 m/s ;

15. V₃(15s-40s) = 4 m/s ; 16. V₁(0s-10s) = 6 m/s > V₄(40s-55s) = 2.67 m/s

Explanation:

The whole movement can be divided into four stages.

In the first stage the subject moves 60m in a positive direction for 10s,

in the other it is stationary for 5s, in the third it moves 100m in the opposite (negative) direction for 25s and in the fourth in the positive 40m for 15s.

11. Total distance = 60 + 0 + 100 + 40 = 200m

12. The formula for calculating the average speed (velocity) is

Vav = (S₁ + S₂ + S₃ + S₄) / (t₁ + t₂ + t₃ + t₄)

Vav = (60 + 0 + 100 + 40)/ (10 + 5 + 25 + 15) = 200/55 = 3.63 m/s

13. The movement started from the origin and ended at the origin

Total displacement is zero meters.

14. The speed between 10s and 15s is zero, because he did not move.

15. V₃ = S₃/t₃ = 100/25 = 4 m/s

16. V₁ = S₁/t₁ = 60/10 = 6 m/s   and V₄ = S₄/t₄ = 40/15 = 2.67 m/s

V₁ > V₄

God is with you!!!

4 0
3 years ago
Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 × 10-5 coulombs is placed on q and a force
kkurt [141]
Formula for feild strength= F/q
q=7.0^10-5 coulombs
F=5.2 N
E=5.2 / 7.0^10-5
E=
7 0
2 years ago
Read 2 more answers
50 POINTS!
zysi [14]

<h3>No:1</h3>

The object is moving with constant or uniform acceleration and in average speed

<h3>No:-2</h3>

The object is de accelerating

<h3>No:-3</h3>

The object deaccelerated and came to rest so fast.

<h3>No:-4</h3>

The object moves slowly first then accelerated.

<h3>No:-5</h3>

The object accelerated at first so fast then move with constant acceleration then again accelerated .

7 0
2 years ago
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