The United States is one country that does not fully use the metric system for measurement.

Chlorine gas (cl2) forms when two chlorine atoms share an electron. what type of bonding is present in chlorine gas?

Masja [62]

Is there some choises

7 0

3 years ago

Ozone gas is a form of elemental oxygen containing molecules with three oxygen atoms, O3. Ozone is produced from atmospheric oxy

adelina 88 [10]

Answer: The unbalanced chemical equation is written below

Explanation:

Unbalanced chemical equation does not follow law of conservation of mass.

In an unbalanced chemical equation, total number of individual atoms on the reactant side will not be equal to the total number of individual atoms on the product side.

The chemical equation for the formation of ozone gas from oxygen gas:

$O_2(g)\rightarrow O_3(g)$

Hence, the unbalanced chemical equation is written above.

8 0

3 years ago

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At room temperature, 20ÁC, water (H2O) is a liquid and oxygen (O2) is a gas. Based on kinetic molecular theory, which answer bes

vaieri [72.5K]

Water molecules have a lower boiling temperature than oxygen molecules, so at room temperature they exist as a liquid rather than a gas.
hope it helps

6 0

3 years ago

Acetylene (c2h2) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. given δh°f[co2(g)] = –393.5

Brums [2.3K]

Answer is: 13181,7 kJ of energy is released when 10.5 moles of acetylene is burned.
Balanced chemical reaction: C₂H₂ + 5/2O₂ → 2CO₂ + H₂O.
ΔHrxn = sum of ΔHf (products of reaction) - sum of ΔHf (reactants).
Or ΔHrxn = ∑ΔHf (products of reaction) - ∑ΔHf (reactants).
ΔHrxn - enthalpy change of chemical reaction.
ΔHf - enthalpy of formation of reactants or products.
ΔHrxn = (2·(-393,5) + (-241,8)) - 226,6 · kJ/mol.
ΔHrxn = -1255,4 kJ/mol.
Make proportion: 1 mol (C₂H₂) : -1255,4 kJ = 10,5 mol(C₂H₂) : Q.
Q = 13181,7 kJ.

8 0

3 years ago

Given that sodium chloride is 39.0% sodium by mass, how many grams of sodium chloride are needed to have 100.mg of Na present? G

seraphim [82]

Answer: The mass of sodium chloride solution present is 0.256 grams.

Explanation:

We are given:

39.0 % of sodium in sodium chloride solution

This means that 39.0 grams of sodium is present in 100 grams of sodium chloride solution

Mass of sodium given = 100 mg = 0.1 g (Conversion factor: 1 g = 1000 mg)

Applying unitary method:

If 39 grams of sodium metal is present in 100 grams of sodium chloride solution

So, if 0.1 grams of sodium metal will be present in = $\frac{100}{39}\times 0.1=0.256g$ of sodium chloride solution.

Hence, the mass of sodium chloride solution present is 0.256 grams.

8 0

3 years ago