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3 years ago

Please answer this, Determine the weight of CaO produced by heating 70 g of CaCO3

1 answer:

6 0

So first you work out the ratio. The formula tells us that for every one 'amount' of Ca and Cthere will be 3x the amount of oxygen. So, the ratio is 1:1:3, (=5) therefore 70g divided by 5 = 14.

If 70g of CaCO3 is heated there will be (1x14) 14g Ca, (1x14) 14g C and (3x14) 42g of O.

Weight of CaO= 42+14, 56g

(I hope this is right! Good luck xx)

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An aluminum can holds 350 mL of gas at 0 C and 1.0 atm. what is the new volume if the can is heated to 10 C and the pressure ins

Mademuasel [1]

Answer:

Final volume of the gas is 4.837mL

Explanation:

Initial volume (V1) = 350mL = 0.35L

Initial temperature (T1) = 0°C = (0 + 273.15)k = 273.15k

Initial pressure (P1) = 1.0atm

Final volume (V2) = ?

Final temperature (T2) = 10°C = (10 + 273.15)k = 283.15K

Final pressure (P2) = 75atm

To solve this question, we'll have to use combined gas equation which is the combination of all gas law I.e Charle's laws, Boyle's law, Pressure law etc.

According to combined gas equation,

(P1 × V1) / T1 = (P2 × V2) / T2

Make V2 the subject of formula,

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (1.0 × 0.35 × 283.15) / (75 × 273.15)

V2 = 99.1025 / 20,486.25

V2 = 0.004837L

V2 = 4.837mL

The final volume of the gas is 4.837mL

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Answer:

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Write a balanced nuclear reaction for the following:

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Balanced nuclear reaction: 234/91 Pa → 4/2 He + 230/89 Ac.
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2) alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four, so atomic mass of new element is 89 (91 - 2) and mass number is 230 (234 - 4 = 230).
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Calculate relative mass of chlorine and boron by the help of given data Only 30 mins are left

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3 years ago

Compound A and compound B are constitutional isomers with molecular formula C3H7Cl. When compound A is treated with sodium metho

mars1129 [50]

Answer:

Compound A and compound B are constitutional isomers with molecular formula C3H7Cl.

When compound A is treated with sodium methoxide, a substitution reaction predominates. When compound B is treated with sodium methoxide, an elimination reaction predominates.

Explanation:

Constitutional isomers are the one which differs in the structural formula.

When compound A is treated with sodium methoxide, a substitution reaction predominates.

That means sodium methoxide is a strong base and a strong nucleophile.

But when it reacts with primary alkyl halides it forms a substitution product and when it reacts with secondary alkyl halide it forms mostly elimination product.

The reaction and the structures of A and B are shown below:

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