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nignag [31]
3 years ago
12

The empirical formula of a hydrocarbon (compound that contains only C and H is found to be CH. laboratory procedures have found

that the molar mass of the compound is 78 g/mol. What is the molecular formula of this compound
Chemistry
1 answer:
gulaghasi [49]3 years ago
6 0

Answer:

C₆H₆

Explanation:

Molar mass of the compound is 78g/mol

Unknown:

Molecular formula of the compound  = ?

Solution:

The empirical formula of the compound is CH.

Empirical formula is the simplest formula of a compound.

To solve this problem:

 Find the molar mass of CH;

       Molar mass = 12 + 1  = 13g/mol

Multiplication index  = \frac{78}{13}    = 6

So;

              (CH)₆  ;

 Therefore:

               C₆H₆

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What does a<br> map<br> scale measure?
d1i1m1o1n [39]

Answer:

Map scale refers to the relationship (or ratio) between distance on a map and the corresponding distance on the ground.

Explanation:

For example, on a 1:100000 scale map, 1cm on the map equals 1km on the ground.

7 0
3 years ago
15. Which sample of argon gas has the same number of atoms as a 100.-milliliter sample of helium gas at 1.0 atm and 300. K? A) 5
OLga [1]

The sample of argon gas that has the same number of atoms as a 100 milliliter sample of helium gas at 1.0 atm and 300 is 100. mL at 1.0 atm and 300. K

The correct option is D.

<h3>What is the number of moles of gases in the given samples?</h3>

The number of moles of gases in each of the given samples of gas is found below using the ideal gas equation.

The ideal gas equation is: PV/RT = n

where;

  • P is pressure
  • V is volume
  • n is number of moles of gas
  • T is temperature of gas
  • R is molar gas constant = 0.082 atm.L/mol/K

Moles of gas in the given helium gas sample:

P = 1.0 atm, V = 100 mL or 0.1 L, T = 300 K

n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

For the argon gas sample:

A. n =  1 * 0.05 / 0.082 * 300

n = 0.00203 moles

B. n =  0.5 * 0.05 / 0.082 * 300

n = 0.00102 moles

C. n =  0.5 * 0.1 / 0.082 * 300

n = 0.00203 moles

D. n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

Learn more about ideal gas equation at: brainly.com/question/24236411

#SPJ1

8 0
1 year ago
Help with chemistry please<br><br>Which chemical reaction involves the most oxygen atoms?
Ratling [72]
H2O is A chemical reaction of the most oxygen atoms
3 0
3 years ago
During combustion, methane yields carbon dioxide and water. The unbalanced equation for this reaction is:CH4(g)+O2(g) → CO2(g)+
almond37 [142]

Answer:

CH₄(g)  +  2O₂(g) → CO₂(g)  +  2H₂O(l)

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2

Explanation:

CH4(g)+O2(g) → CO2(g)+ H2O(l)

To balance a chemical equation, you must have the same mole of each element in both sides of the reaction (reactant side and product side)

CH₄(g)  +  2O₂(g) → CO₂(g)  +  2H₂O(l)

2 C

8 H

8 O

In  both side.

It takes 1 mole of methane to react with 2 mole of oxygen in order to produce 1 mol of dioxide and 2 mole of water.

Mole ratios for the balanced equation be:

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2  - We should compare each compound

1 mol methane → 2 mole of oxygen

2 mole of oxygen → 1 mol of methane

2 mole of oxygen → 1 mol of dioxide

1 mole of dioxide → 1 mol of Methane

2 mole of water → 2 mole of oxygen (the same as opposite)

1 mol methane →  2 mole of water

2 mol of water → 1 mol of methane

4 0
3 years ago
Sighting along the C2-C3 bond of 2-methylbutane, the least stable conformation (Newman projection) has a total energy strain of
natima [27]

Answer:

21 KJ/mol

Explanation:

For this question, we have to start with the <u>linear structure</u> of 2-methylbutane. With the linear structure, we can start to propose all the <u>Newman projections</u> keep it in mind that the point of view is between carbons 2 and 3 (see figure 1).

Additionally, we have several <u>energy values for each interaction</u> present in the Newman structures:

-) Methyl-methyl <em>gauche: 3.8 KJ/mol</em>

-) Methyl-H <em>eclipse: 6.0 KJ/mol</em>

-) Methyl-methyl <em>eclipse: 11.0 KJ/mol</em>

-) H-H <em>eclipse:</em> 4.0 KJ/mol

Now, we can calculate the energy for each molecule.

<u>Molecule A</u>

In this molecule, we have 2 Methyl-methyl <em>gauche </em>interactions only, so:

(3.8x2) = 7.6 KJ/mol

<u>Molecule B</u>

In this molecule, we have a Methyl-methyl <em>eclipse </em>interaction a Methyl-H <em>eclipse </em>interaction and an H-H <em>eclipse</em> interaction, so:

(11)+(6)+(4) = 21 KJ/mol

<u>Molecule C</u>

In this molecule, we have 1 Methyl-methyl <em>gauche </em>interaction only, so:

3.8 KJ/mol

<u>Molecule D</u>

In this molecule, we have three Methyl-H <em>eclipse </em>interaction, so:

(6*3) = 18 KJ/mol

<u>Molecule E</u>

In this molecule, we have 1 Methyl-methyl <em>gauche </em>interaction only, so:

3.8 KJ/mol

<u>Molecule F</u>

In this molecule, we have a Methyl-methyl <em>eclipse </em>interaction a Methyl-H <em>eclipse </em>interaction and an H-H <em>eclipse</em> interaction, so:

(11)+(6)+(4) = 21 KJ/mol

The structures with higher energies would be less stable. In this case, structures B and F with an energy value of 21 KJ/mol (see figure 2).

I hope it helps!

3 0
4 years ago
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