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andriy [413]
3 years ago
12

Floor 19 is an isotope of fluorine It has different number of?—————

Chemistry
1 answer:
vitfil [10]3 years ago
5 0
Try B, but i don’t know
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A proton travels at a speed of 2.0 × 106 meters/second. Its velocity is at right angles with a magnetic field of strength 5.5 ×
Finger [1]

So here we are given that the the velocity of the proton ( V ) is 2.0 × 10^6 meters / second, with a magnetic field of strength 5.5 × 10^{-3}  tesla. If they each form a right angle, they are hence perpendicular to one another, such that ....

F = q( V × B ),

F = q v B( sin ∅ ),

F = q v B( sin( 90 ) )

.... they form the following formula. Let's go through each of the variables in our formula here -

{ F = Magnetic Force ( which has to be calculated ), q = charge of proton (has charge of 1.602 × 10^{19} coulombs ), B = magnetic field }

All we have to do now is plug and chug,

F = ( 1.602 × 10^{19} )( 2.0 × 10^6 )( 5.5 × 10^{-3} ) = ( About ) 1.8 × 10^{-15} Newtons

6 0
3 years ago
How many grams of FeS2 are needed to react with 95 g O2?
Rainbow [258]

Answer:

16.0  i think

Explanation:

4 0
3 years ago
T = 409.5 K, P = 1.50 atm: V = ?L
Molodets [167]

Explanation:

T = 409.5 K, P = 1.50 atm: V = 22.4 L The ideal gas law is: PV = nRT where. P = pressure. V = volume n = number of moles.

7 0
2 years ago
Please help me! I will fail science if I don’t finish this test :(
Tasya [4]

Answer:

<h2>A. Mercury's orbit is shorter than Earth</h2>
6 0
3 years ago
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
3 years ago
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