Based on the enthalpy of the reaction, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
<h3>What is heat of reaction?</h3>
The heat of reaction or enthalpy change is the heat absorbed or evolved when reactant molecules react to form products.
According the enthalpy value of the reaction, 4 moles of ammonia require 1530 kJ of heat for its formation.
Molar mass of ammonia = 17 g
Mass of 4 moles of ammonia = 4 × 17 = 68 g
1850 g of ammonia will require = 1850 × 1530/68 = 41625 kJ of heat.
Therefore, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
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The substances largely ionic are:
NF3
N2
BrF3
PCl3
Answer:
1.68 × 10²³ Molecules
Explanation:
As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (molecules) contained by 0.280 moles of Br₂, we will use following relation,
Moles = Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹
Solving for Number of Molecules,
Number of Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹
Putting values,
Number of Molecules = 0.280 mol × 6.022 × 10²³ Molecules.mol⁻¹
Number of Molecules = 1.68 × 10²³ Molecules
Hence,
There are 1.68 × 10²³ Molecules present in 0.280 moles of Br₂.
