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vlabodo [156]
3 years ago
11

Football Player Position Mass (kg) Velocity (m/s) Half back 60 8 Tight end 90 6 Full back 110 5 Lineman 120 3 Based on the data

shown in the table, what is most likely being tested? A) Does the speed of a player affect his mass? B) How are mass and speed related in football? C) Which positions have the fastest speed and biggest mass? Eliminate D) How does the speed of a player change as his mass is increased?
Chemistry
2 answers:
katrin [286]3 years ago
5 0
Whether the speed of the player is affected by his weight is being tested.
A) The speed is affected by the player's mass.
B) As the mass increases, the velocity of the player decreases.
C) The fastest speed is the Half Back and the biggest mass if Lineman.
D) As the mass increases, the velocity of the player decreases.
Andreas93 [3]3 years ago
4 0

Answer:

D) How does the speed of a player change as his mass is increased

Explanation:

Since the data in the table shows us a clear increase in mass first, and a decrease in velocity corresponding to that increase in mass, the study most likely is trying to research the effects of an increase in the mass of the player and how it would affect its velocity. AS you can see in the table, the most heavy players are also the slowest and the quickest players are also the thinest, so there is a direct inverse correlationship.

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Carbon dioxide (CO2) fills a closed, rigid tank fitted with a paddle wheel, initially at 80°F, 30 lbf/in2, and a volume of 1.6 f
solong [7]

Answer:

The answer to this question can be given as:  

The initial pressure P= 30 lbf/in2

The initial temperature T1=80°F.

The initial volume=final volume V= 1.6 ft3.

Final  temperature T2=500°F

Heat transfer Q=-2.6 Btu.

pressure (P) (lbf/in2) change into lbf/ft2

P=30 lbf/in2=4320lbf/ft2.

Temperature (T1) °F change into °K

temperature T1=80°F=539.67 °K

Ideal gas formula:

M=PV/RT1.                   where T1=initial temperature.

M=4320*1.6/35.114*539.67.

M=0.364749 lb             Mass at Carbon dioxide (CO2).

DQ=DU+W            second law.

-2.6=MCV(T2-T1)+ W        

-2.6-(0.364749*1.6(500-80))=W

W=-27.111 b+u  am----> work done.

Explanation:

The explanation to this question can be given as:

Firstly we write the equation that is given in the question like, pressure, volume, gas constant, temperature. Then we covert the pressure and temperature into there possible values. Then We apply the formula of Ideal gas that is  M=PV/RT1. where M is  the mass, P is the pressure , V is the volume , R is the gas constant (0.08206 L·atm·K−1·mol−1)  and T1 is the initial temperature. Then we use the second formula that is DQ=DU+W. Where DQ= Heat transfer, DU=MCV(T2-T1)and W= work. It is used for finding work.

8 0
3 years ago
Which choice has prokaryotic cells?
creativ13 [48]
The answer is E. coli
8 0
3 years ago
Reacting Solutions of Aluminum Chloride with Potassium Hydroxide
gizmo_the_mogwai [7]

1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4

The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.

Now add all the coefficients/moles.

9 is the sum of all the coefficients.

7 0
2 years ago
Read 2 more answers
Grade 8 Science
ira [324]
Materials<span> and their </span>properties<span>: </span>compounds like<span> sodium chloride - an interactive educational resource for 11 to 14 year olds. ... Elements are substances (</span>like<span> hydrogen and oxygen) that can't be split into simpler substances. ... For </span>each<span> statement, decide whether it describes a mixture or a </span>compound<span> and check the box.</span>
8 0
3 years ago
Select the true statements about hydrocarbons.
daser333 [38]

Answer:

a. Hydrocarbons have low boiling points compared to compounds of similar molar mass.

b. Hydrocarbons are hydrophobic.

d. Hydrocarbons are insoluble in water.

Explanation:

As we know that the hydrocarbons is a mix of carbon and hydrogen. In this the availability of the electronegative atom is not there that shows there is no bonding of the hydrogen plus it is dissolved. Also, the hydrocarbons is considered to be a non-polar but as compared to the water, water is a polar

In addition to this, the strong bond is no existed that shows the lower boiling points  

Therefore option A, B and D are right

8 0
3 years ago
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