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vlabodo [156]
3 years ago
11

Football Player Position Mass (kg) Velocity (m/s) Half back 60 8 Tight end 90 6 Full back 110 5 Lineman 120 3 Based on the data

shown in the table, what is most likely being tested? A) Does the speed of a player affect his mass? B) How are mass and speed related in football? C) Which positions have the fastest speed and biggest mass? Eliminate D) How does the speed of a player change as his mass is increased?
Chemistry
2 answers:
katrin [286]3 years ago
5 0
Whether the speed of the player is affected by his weight is being tested.
A) The speed is affected by the player's mass.
B) As the mass increases, the velocity of the player decreases.
C) The fastest speed is the Half Back and the biggest mass if Lineman.
D) As the mass increases, the velocity of the player decreases.
Andreas93 [3]3 years ago
4 0

Answer:

D) How does the speed of a player change as his mass is increased

Explanation:

Since the data in the table shows us a clear increase in mass first, and a decrease in velocity corresponding to that increase in mass, the study most likely is trying to research the effects of an increase in the mass of the player and how it would affect its velocity. AS you can see in the table, the most heavy players are also the slowest and the quickest players are also the thinest, so there is a direct inverse correlationship.

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Jlenok [28]

Explanation:

If we have the following reaction at equilibrium:

<em>                                           aA + bB ⇄ cC + dD</em>

where a, b, c, and d are the stoichiometric coefficients for the reacting species A, B,  C, and D. For the reaction at a particular temperature:

                       Kc=([C]^c *[D]^d)/([A]^a *[B]^b)

where Kc is the equilibrium constant, which holds that <em>for a reversible reaction at equilibrium  and a constant temperature, a certain ratio of reactant and product concentrations has  a constant value, Kc</em> (the equilibrium constant). Note that although the concentrations  may vary, as long as the reaction in in equilibrium and temperatura don't change, the value of <u>K remains constant.</u>

For reactions that have not reached equilibrium, we obtain the reaction quotient (Qc), instead of the equilibrium  constant <u>by substituting the initial concentrations into the equilibrium constant expression.</u>

                        Qc=([Co]^c *[Do]^d)/([Ao]^a *[Bo]^b)

To determine the direction in wich the net reaction will proceed to reach equilibrium, que compare the values of Qc and Kc.

  • Qc < Kc: To reach equilibrium, reactants must be converted to products (→)
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  • Qc > Kc: To reach equilibrium, products must be converted to reactants (←)

Solution:

We have the following reaction:

                             NO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)

So:

Kc=([NOCl]^1*[NO2]^1)/([NO2Cl]^1 *[NO]^1)

     =([NOCl][NO2])/([NO2Cl][NO])  

1. In the equation above, [NO2Cl] it's in the denominator, so if we increase it's numericall value by adding NO2Cl <u>decreases Qc  to a value less than Kc.</u>

<em>(From the chemical point of view, if we disturb the equilibrium adding NO2Cl (a reactant), to reach equilibrium again the system proceeds from left to right (→) consuming this reactant.)</em>

2. To reach a new state of equilibrium (<em>where Qc = Kc</em>), Qc therefore  increases wich means that the denominator of the expression for Qc  decreases <em>(in order to increase the denominator as mention above).</em>

3. To accomplish this, the concentration of reageants decreases <em>(reagents are being consumed), </em>and the concentration of prodcuts increases <em>(products are being formed).</em>

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dsp73

The number of moles that are contained in the given mass of propane (C_3H_8 is 1.7143 moles.

<u>Given the following data:</u>

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<u>Scientific data:</u>

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To calculate the number of moles that are contained in the given mass of propane (C_3H_8):

<h3>How to calculate the moles of a compound.</h3>

In this exercise, you're required to determine the number of moles of propane that are contained in the given sample:

Mathematically, the number of moles contained in a chemical compound is given by this formula:

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Substituting the given parameters into the formula, we have;

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neutrons   1.675*10 ^ - 27 kg        0                             in the nucleus
electron     9.11 * 10 ^ - 31 kg       -1.6 * 10 ^ - 19 C    around the nucleus (orbitals)

Protons and neutrons have almost same masses. Mass of electrons is 1/1840 the mass of the protons.

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