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Yakvenalex [24]
2 years ago
12

Agustina was standing on the edge of a cliff of unknown height holding a bowling ball. She wanted to find the height of the clif

f. She worked with Maite to time the how long the bowling took to fall to the bottom of the cliff. Maite timed the drop at 9.4 seconds on each of their 10 trials. The bowling ball started at rest on each of the trials. What distance did the bowling ball fall in each trial?
Chemistry
1 answer:
nlexa [21]2 years ago
5 0

Answer:

433 m

Explanation:

Since the fall represents motion under gravity, we use the equation

s = ut - 1/2gt² where s = height of cliff or distance bowling ball falls through, u = initial velocity of bowling ball = 0 m/s(since it starts from rest), t = time = 9.4 s and g = acceleration due to gravity = -9.8 m/s².

So, substituting the values of the variables into the equation, we have

s = 0 m/s × 9.4 s - 1/2 × 9.8 m/s² × (9.4 s)²

s = 0 m - 1/2 × -9.8 m/s² × 88.36 s²

s = 1/2(865.928 m)

s = 432.964

s ≅ 433 m

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Answer:

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Explanation:

According to the law of conservation of energy, the sum of the heat absorbed by water (Qw) and the heat released by the coffee (Qc) is zero.

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163 mL of coffee with a density of 0.997 g/mL have a mass of:

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From [1]

Qw = -Qc

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mw × (54.0°C-25.0°C) = -163 g × (54.0°C-97.9°C)

mw × 29.0°C = 163 g × 43.9°C

mw = 247 g

The volume corresponding to 247 g of water is:

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