Answer: addition of electrons and hydrogen ions. loss of electrons and addition of hydrogen ions. loss of electrons and either addition or loss of hydrogen ions.
Answer:
E/4
Explanation:
The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:
E = σ/(2ε₀)
Where;
E is the electric field
σ is the surface charge density
ε₀ is the electric constant.
Formula to calculate σ is;
σ = Q/A
Where;
Q is the total charge of the sheet
A is the sheet's area.
We are told the elastic sheet is a square with a side length as d, thus ;
A = d²
So;
σ = Q/d²
Putting Q/d² for σ in the electric field equation to obtain;
E = Q/(2ε₀d²)
Now, we can see that E is inversely proportional to the square of d i.e.
E ∝ 1/d²
The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.
From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;
E_new = E/4
Answer:
The electric field is directed toward the electron and has a magnitude of
.
Explanation:
An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.
In the given case electron is given and the magnitude of charge on electron is 
Electric field can be represented as,

Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.
In the given question an electron is given so electric field will be,

As we know that electric field start from the positive charge and vanish in the negative charge.
So, here the electric field will be
and it is directed toward the electron because of negative charge on the electron.
<h2>
Velocity of the boat with respect to Earth is 5 m/s 56.31° north of east</h2>
Explanation:
A boat heads north in still water at 4.5 m/s directly across a river that is running east at 3.0 m/s.
Let north be positive y axis and east be positive x axis.
We have
Velocity of boat = 4.5 j m/s
Velocity of river = 3 i m/s
Velocity of the boat with respect to Earth = 3 i + 4.5 j


That is 56.31° north of east.
Velocity of the boat with respect to Earth is 5 m/s 56.31° north of east
All life on Earth; plants, animals, etc. Anything that is alive is part of the biosphere.